Complete Question:
The expression 16t² represents the distance in feet an object falls after t seconds. The object is dropped from a height of 906 feet. What is the height in feet of the object 2 seconds after it is dropped?
Answer:
H(2) = 842 feet
Step-by-step explanation:
Let the height be H.
<u>Given the following data;</u>
H(t) = 16t²
Height, H = 906 feet
Time, t = 2 seconds
To find the time, t at 2 seconds, we would use the following formula;
H(t) = H - 16t²
H(2) = 906 - 16(2)²
H(2) = 906 - 16*4
H(2) = 906 - 64
<em>H(2) = 842 feet</em>
<em>Therefore, the height in feet of the object 2 seconds after it is dropped is 842.</em>
Answer:
50
Step-by-step explanation:
Hi,
-5x = -115
-115/-5 = 23
-5 × 23 = -115
The answer is 23
Hope this helps! :)
(a). 8x + y = 20, where (b). y = x2 - 2x + 4
So where y is in equation (a), substitute in the value of y in (b).
8x + (x2 - 2x + 4) = 20
8x + (4) = 20
Get rid of the 4 on both sides (since what you do to one side, you must do to the other)
8x + 4 - 4 = 20 - 4
8x = 16
Get rid of the 8 to leave x on its own
8x ÷ 8 = 16 ÷ 8
x = 2
So now that you have x, find y but substituting in the value you just found (2) into one of the starting equations.
8x + y = 20 where x is 2.
8(2) + y = 20
16 + y = 20
Minus 16 from both sides
y = 20 - 16 = 4
So x is 2 and y is 4
