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Alexxx [7]
3 years ago
10

Mr.Clark shared a quantity of mangoes among his 3 sons,Drake,Rafael and John in a ratio of 3:2:4 respectively. Drake received 63

mangoes,calculate the total quantity of mangoes Mr.Clark had.​
Mathematics
2 answers:
Mariulka [41]3 years ago
7 0

Answer:

Drake is 63

Rafael is 42

John is 84

Step-by-step explanation:

Mangoes

Firlakuza [10]3 years ago
4 0

Drake: 63 Mangoes

Rafael: 42 Mangoes

John: 84 Mangoes

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dem82 [27]

Answer: 1/x

Step-by-step explanation:

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Use the factor tree to find the prime factorization of 100.
Stolb23 [73]

Answer:

2 x 2 x 5 x 5

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8 0
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Read 2 more answers
I'll give more points here is what I need.
Serga [27]

Answer:

The answer to your question is x = 3; y = 3

Step-by-step explanation:

Data

angle = 45°

Opposite side = x

Adjacent side = y

hypotenuse = 3√2

To solve this problem, use trigonometric functions.

1) To find x, use the trigonometric function sine.

              sin Ф = Opposite side / hypotenuse

-Solve for Opposite side (x)

              Opposite side = hypotenuse x sin Ф

-Substitution

              Opposite side = 3√2 sin 45

-Simplification

               Opposite side = 3√2 (1 / √2)

               Opposite side = 3(1)

-Result  

               x = 3

2) To find y use the trigonometric function cosine

               cos Ф = Adjacent side / hypotenuse

-Solve for Adjacent side

                Adjacent side = hypotenuse x cos Ф

-Substitution

                Adjacent side = 3√2 x cos 45

-Simplification

                Adjacent side = 3√2 x (1/√2)

                Adjacent side = 3(1)

-Result

                y = 3

5 0
3 years ago
An urn contains nine red and one blue balls. A second urn contains one red and five blue balls. One ball is removed from each ur
il63 [147K]

Answer:

0.362

Step-by-step explanation:

When drawing randomly from the 1st and 2nd urn, 4 case scenarios may happen:

- Red ball is drawn from the 1st urn with a probability of 9/10, red ball is drawn from the 2st urn with a probability of 1/6. The probability of this case to happen is (9/10)*(1/6) = 9/60 = 3/20 or 0.15. The probability that a ball drawn randomly from the third urn is blue given this scenario is (1 blue + 5 blue)/(8 red + 1 blue + 5 blue) = 6/14 = 3/7.

- Red ball is drawn from the 1st urn with a probability of 9/10, blue ball is drawn from the 2nd urn with a probability of 5/6. The probability of this event to happen is (9/10)*(5/6) = 45/60 = 3/4 or 0.75. The probability that a ball drawn randomly from the third urn is blue given this scenario is (1 blue + 4 blue)/(8 red + 1 blue + 1 red + 4 blue) = 5/14

- Blue ball is drawn from the 1st urn with a probability of 1/10, blue ball is drawn from the 2nd urn with a probability of 5/6. The probability of this event to happen is (1/10)*(5/6) = 5/60 = 1/12. The probability that a ball drawn randomly from the third urn is blue given this scenario is (4 blue)/(9 red + 1 red + 4 blue) = 4/14 = 2/7

- Blue ball is drawn from the 1st urn with a probability of 1/10, red ball is drawn from the 2st urn with a probability of 1/6. The probability of this event to happen is (1/10)*(1/6) = 1/60. The probability that a ball drawn randomly from the third urn is blue given this scenario is (5 blue)/(9 red + 5 blue) = 5/14.

Overall, the total probability that a ball drawn randomly from the third urn is blue is the sum of product of each scenario to happen with their respective given probability

P = 0.15(3/7) + 0.75(5/14) + (1/12)*(2/7) + (1/60)*(5/14) = 0.362

8 0
3 years ago
How to do the problem
trapecia [35]

Step-by-step explanation:

g(0.5) = 2 \\  \\ h(x) = g(x).f(x) \\  \therefore \: h(2) = g(2).f(2) \\  \therefore \: h(2) = 5 \times 2\\ \therefore \: h(2) = 10\\  \\ \\  j(x) = g(x) - f(x) \\  \therefore \: j(4) = g(4) - f(4) \\  \therefore \: j(4) = 9 - 8\\ \therefore \: j(4)  = 1\\  \\  \\

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3 years ago
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