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3 years ago

7

Find the range of the function

1 answer:

Gnesinka [82]3 years ago

7 0

Answer:

It would be <em>A</em>

Step-by-step explanation:

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Help please anybody which too are correct

liraira [26]

the 1st and 2nd ones r correct

Step-by-step explanation:

hope this helps

5 0

3 years ago

Can someone describe the lower bounds theorem?

prisoha [69]

The lower bound is the smallest value that would round up to the estimated value. A quick way to calculate upper and lower bands is to halve the degree of accuracy specified, then add this to the rounded value for the upper bound and subtract it from the rounded value for the lower bound.

8 0

3 years ago

Consider the following points.

horrorfan [7]

Answer:

(a) $P(x)=0.4x^{3} +2x^{2} -1.4x$

(b) $P(x)=x^{4} -x^{3} +5x^{2} -7x-14$

Step-by-step explanation:

Let´s use Divided Differences Method of Polynomial Interpolation given by this iteration:

$f[x_k,x_k_+_1,...,x_k_+_i]=\frac{f[x_k_+_1,x_k_+_2,...,x_k_+_i]-f[x_k,x_k_+_1,...,x_k_+i_-_1]}{x_k_+_i-x_k}$

k∈[0,n-i]

Thus the Newton polynomial can be written as:

$P_n_-_1(x)=f[x_0]+f[x_0,x_1](x-x_0)+f[x_o,x_1,x_2](x-x_0)(x-x_1)+...+f[x_n,x_n_-_1,...,x_1](x-x_n)(x-x_n_-_1)...(x-x_1)$

(a) I attached you the procedure in the first table, using it we have:

$P(x)=3+(-3)(x+1)+(2)(x+1)(x)+0.4(x+1)(x)(x-1)$

Operate P(x) using the distributive property:

$P(x)=0.4x^{3} +2x^{2} -1.4x$

(b) I attached you the procedure in the second table, using it we have:

$P(x)=44+(-44)(x+2)+(15)(x+2)(x+1)+(-3)(x+2)(x+1)(x)+(1)(x+2)(x+1)(x)(x-1)$

Operate P(x) using the distributive property:

$P(x)=x^{4} -x^{3} +5x^{2} -7x-14$

6 0

3 years ago

Please help me before I fail... I really need some help <3 please ;-;

GuDViN [60]

Answer:

sin( 61) = x/55

55(sin(61)) = x

48.1 = x

Hope this helps!

4 0

3 years ago

Find the area of a triangle with a base of 8 cm and a height of 10 cm

Alexandra [31]

Answer:

<h2>A = 40 cm²</h2>

Step-by-step explanation:

The formula of an area of a triangle:

$A_\triangle=\dfrac{b\cdot h}{2}$

<em>b</em><em> - base</em>

<em>h</em><em> - height</em>

<em />

We have <em>b = 8cm, h = 10cm</em>.

Substitute:

$A=\dfrac{(8)(10)}{2}=\dfrac{80}{2}=40\ (cm^2)$

6 0

3 years ago