Answer:
f(x)=x^2+3
f(x+y)=(x+y)^2+3
this is done by replacing x with (x+y)
f(x+y)=x^2+2xy+y^2+3
therefore : f(x+y)= x^2+y^2+2xy+3
The function f(x) is defined in to different ways depending on the value of X. When x is < 5, use the expression 2x - 1 to evaluate the function When x is ≥ 5, use the expression x2 - 3 for example f(1) = 2(1) - 1 = 1 f(10) = (10)2 - 3 = 97
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2.8y + 6 + 0.2y = 5y - 14
(Simplify like terms in first half of equation)
3y + 6 = 5y - 14
(Subtract both sides by 3y)
6 = 2y - 14
(Flip)
2y - 14 = 6
(Add both sides by 14)
2y = 20
(Divide both sides by 2)
y=10
