The question here is how long does it take for a falling
person to reach the 90% of this terminal velocity. The computation is:
The terminal velocity vt fulfills v'=0. Therefore vt=g/c,
and so c=g/vt = 10/(100*1000/3600) = 36,000/100,000... /s. Incorporating the
differential equation shows that the time needed to reach velocity v is
t= ln [g / (g-c*v)] / c.
With v=.9 vt =.9 g/c,
t = ln [10] /c = 6.4 sec.
Answer: -300 meters
Step-by-step explanation: If he started from 0 (sea level) and went 300 meters under, meaning 0-300=-300 meters.
Step-by-step explanation:
let m2 be x
then m1 = 4x
Since, m1+m2 = 115
therefore x + 4x = 115
5x = 115
x = 23
so , m2 = 23°
Answer: y = (-4/5)x + 8
Solution
The equation of line is
y = mx + b
Where
y = y coordinate
m = slope
x = x coordinate
b = y intercept
In order to write the equation of line we need to find the y-intercept (b)
substitute the slope (-4/5) and coordinates given (0,8) ,
y = mx + b
8 = -4/5 (0) + b
8 = b
So,
y = (-4/5)x + 8
Hello!
Are you looking for how many "Terms" there are?
If so, then there would be: 5 terms, which are:
a³
3a²b
-4ab
-11b
7
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