1. C=2πr
We need to move r by itself on a side of the equation.
Divide both sides of the equation by 2π. This will cancel out the side with the r.
r=C/2π
2. A=1/2*b*h
Divide both sides by 1/2*h, isolating b
b=A/
h
3.y=mx+b
Now we have to do reverse PEMDAS, we have to add/subtract before we can multiply or divide to simplify.
Subtract both sides by b
y-b=mx
Now divide both sides by m
x=
Remember we have to divide both terms y and -b by 2, so it goes on the bottom for both.
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(10 + a / 2, 2 + b / 2) = (8, 1)
10 + a / 2 = 8
10 + a = 16
a = 6
2 + b / 2 = 1
2 + b = 2
b = 0
so V(6, 0)
Hello here is a solution :
f'(x) =( sin11x)'cos11x +<span>sin11x(cos11x)'
(sin(ax+b))'=a cos(ax+b)
</span>(cos(ax+b))'=-a sin(ax+b)
f'(x) = 11 cos11xcos11x-11sin11xsin11x
f'(x) = 11(cos11x)²-11(sin11x)²
Answer:
Ans
Step-by-step explanation:
In Q. No. F, 1st page last step there is /2.
OK