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Veseljchak [2.6K]
3 years ago
6

Given the line 2x - 3y - 5 = 0, find the slope of a line that is perpendicular to this line.

Mathematics
2 answers:
shusha [124]3 years ago
8 0
<span>2x - 3y - 5 = 0
3y = 2x - 5
  y = 2/3 x - 5/3 so this line has slope = 2/3
perpendicular lines, slope is opposite and reciprocal
so slope = -3/2

answer
-3/2</span>
mojhsa [17]3 years ago
3 0
The Slope of "<span>2x - 3y - 5 = 0" is:

m = 2/3.

Use the mx+y formula to solve this question.  

The correct answer is: B 

This is a verified answer.  </span>
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Step-by-step explanation:

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6 0
3 years ago
Multiple or divide as indicated 2x/4x+2 x 14 x+7/6
otez555 [7]
<span>2x/4x+2 x 14 x+7/6 is unclear.  Do you mean 2/4x, or do you mean  2x
                                                                                                           --------  ??
                                                                                                            4x+2
Use parentheses to make things clearer.

I will assume that you meant to write

   2x
--------- * 14x + 7/6
4x + 2

but am very much unsure if this is correct or not.



Perhaps you meant 

</span>2x/(4x+2) times 14(x+7/6)
<span>
This comes out as follows:

 2x * 14 (x + 7/6)        28x(x + 7/6)        14x(x + 7/6) 
------------------------ = ------------------- = --------------------
       4x+2                        2(2x + 1)              2x + 1         after reduction.

Performing the multiplication, we get            14x^2 + 98/6
                                                                     --------------------
                                                                              2x+1
</span>  

It appears that you're using "x" both as a variable name and as the "multiply" operator.  If so, please don't!  Use " * " to indicate multiplication.
<span>
</span>Please take and share a screen shot of this problem.
3 0
3 years ago
What is U over 72=2 over 4
Mademuasel [1]
U/72 = 2/4

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therefore u = 72*0.5

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8 0
4 years ago
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<em><u>ex:</u></em><u /><u><em /></u><em />

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Hoochie [10]
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