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3 years ago

Is (0,5) a solution to the equation y=2x?

Mathematics

2 answers:

Illusion [34]3 years ago

5 0

Answer:

Step-by-step explanation:

The coordinate points are x and y.

So, in this case, 0 would be x and 5 would be y.

We can substitute those numbers into our equation to get:

5=(2)(0)

2 multiplied by 0 equals 0.

0 CANNOT equal 5.

Therefore, your answer is NO, (0,5) isn't the solution to the equation y=2x.

-Stay smart, stay golden :)

klio [65]3 years ago

3 0

Answer:

No.

Step-by-step explanation:

If (0,5) is a solution to y=2x, then 5=2(0) has to be true.

It is not because 5=2(0) is not true.

2(0)=0 and 0 is definitely not 5.

An example of a point on y=2x is (5,10) since 10=2(5) is true.

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2 years ago

Solve for b. 3-2(b - 2) = 2 - 7b

malfutka [58]

Answer:

b = -1

Step-by-step explanation:

use distributive property to multiply the -2 with the numbers in the parentheses

3 - 2b + 4 = 2 - 7b

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divide by -5

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3 years ago

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Given that P = (-7, 16) and Q = (-8, 7), find the component form and magnitude of vector QP .

Katyanochek1 [597]

Answer:

a)The component form is

$\vec {QP}=\binom{ - 1}{ - 8}$

b)The magnitude is √65

c) <2,14>

Step-by-step explanation:

Recall that:

$\vec {QP}=\vec {OP}-\vec{OQ}$

We substitute the position vectors to get:

$\vec {QP}=\binom{ - 8}{7} - \binom { - 7}{15}$

We subtract the corresponding components to obtain:

$\vec {QP}=\binom{ - 8 - - 7}{7 - 15}$

This gives:

$\vec {QP}=\binom{ - 8 + 7}{7 - 15}$

This simplifies to:

$\vec {QP}=\binom{ - 1}{ - 8}$

The magnitude of a vector in the component form:

$\binom{x}{y}$

$\sqrt{ {x}^{2} + {y}^{2} }$

This means:

$|\vec {QP}|= \sqrt{ {( - 1)}^{2} + {( - 8)}^{2} }$

This simplifies to:

$|\vec {QP}| = \sqrt{ 1 + 64 }$

$|\vec {QP}| = \sqrt{ 65 }$

c) We have the vectors u = <4, 8>, v = <-2, 6>.

We want to find:

u+v

This implies that:

u+v=<4,8>+<-2,6>

We add the corresponding components to get;

u+v=<4+-2,8+6>

This simplifies to:

u+v=<2,14>

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3 years ago

Y=x+1 3x-2y=5 solve using substitution

miskamm [114]

Answer: (4, 5)
Work:
Substitute the y in the second problem with y=x+1
3x-2(x+1)=5
3x-2x+1=5
x=4
Now solve for y
y=4+1
y=5

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Step-by-step explanation:

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Is (0,5) a solution to the equation y=2x?​

Is (0,5) a solution to the equation y=2x?