1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
UNO [17]
3 years ago
5

A computer program is tested by 5 independent tests. If there is an error, these tests will discover it with probabilities 0.1,

0.2, 0.3, 0.4, and 0.5, respectively. Suppose that the program contains an error. What is the probability that it will be found
Computers and Technology
1 answer:
Svetllana [295]3 years ago
5 0

Answer:

0.8488

Explanation:

Let E =error found by test 1

Let F=error found by test 2

Let G=error found by test 3

Let H=error found by test 4

Let I= error found by test 5

Given P(E)=0.1, P(F)=0.2, P(G)=0.3, P (H)= 0.4, P (I)=0.5

therefore P(notE)=0.9, P(notF)=0.8, P(notG)=0.7, P(not H)=0.6, P (notI)=0.5

Tests are independent P(not E & not F &not G & not H & not I=P(notE)*P(notF)*P(notG)*P (notH)*P (not I) =0.9*0.8*0.7*0.6*0.5 =0.1512

P(found by at least one test)= 1- P(not found by any test)=1-P(not E& not F & not G & not H & not I ) = 1-0.1512 = 0.8488

You might be interested in
Build three classes that conform to the following interfaces. Use arrays in creating your classes (e.g., do not use the built-in
daser333 [38]

Explanation:

public class ArrayList {

private Object[] array = new Object[1];

/**

 * Places new element at location

 * @param c, element to be inserted

 * @param i, location it is to be placed

 */

public void insert(char c, int i) {

 if(i>this.size()){

  System.out.println("Index "+i +" outside of list size; max: " +this.size());

  System.exit(0);

 }

 int count = 0;

 try {

  Object[] other = new Object[this.array.length+1];

  switch(i){

     case 0:{

      other[0] = c;

      for(int j=1;j<this.array.length;j++)

       other[j] = this.array[j-1];

       

      this.array = other;

      break;

     }

     default: {

      for(int j=0;j<i;j++)

       other[j] = this.array[j];

      other[i] = c;

      for(int k=i+1;k<this.array.length;k++)

       other[k] = this.array[k-1];

      this.array = other;

      break;

     }

     }

 }

 catch(ArrayIndexOutOfBoundsException exception) {

     largerArray();

     if(++count == 2){

      System.out.println("Something went wrong.");

      System.exit(0);

     }  

 }

}

 

/**

 * Places new element at location

 * @param object, element to be inserted

 * @param index, location it is to be placed

 */

void insert(Object object, int index){

 if(index>this.size()){

  System.out.println("Index "+index +" outside of list size; max: " +this.size());

  System.exit(0);

 }

 int count = 0;

 try {

  Object[] other = new Object[this.array.length+1];

  switch(index){

     case 0:{

      other[0] = object;

      for(int j=1;j<this.array.length;j++)

       other[j] = this.array[j-1];

       

      this.array = other;

      break;

     }

     default: {

      for(int j=0;j<index;j++)

       other[j] = this.array[j];

      other[index] = object;

      for(int k=index+1;k<this.array.length;k++)

       other[k] = this.array[k];

      this.array = other;

      break;

     }

     }

 }

 catch(ArrayIndexOutOfBoundsException exception) {

     largerArray();

     if(++count == 2){

      System.out.println("Something went wrong.");

      System.exit(0);

     }  

 }

}

 

/**

 * Removes element at index

 * @param index, location to remove

 * @return temp, object removed

 */

Object remove(int index){

 if(index>this.size()){

  System.out.println("Index "+index +" outside of list size; max: " +this.size());

  System.exit(0);

 }

 Object temp = this.array[index];

 int count = 0;

 try {

  Object[] other = new Object[this.array.length-1];

  switch(index){

     case 0:{

      other[0] = this.array[1];

      for(int j=1;j<this.size();j++)

       other[j] = this.array[j+1];

       

      this.array = other;

      break;

     }

     default: {

      for(int j=0;j<index;j++)

       other[j] = this.array[j];

      for(int k=index;k<this.size();k++)

       other[k] = this.array[k+1];

      this.array = other;

      break;

     }

     }

 }

 catch(ArrayIndexOutOfBoundsException exception) {

     largerArray();

     if(++count == 2){

      System.out.println("Something went wrong.");

      System.exit(0);

     }  

 }

 return temp;

}

 

/**

 * Copies the array to a new array twice the size.

 */

public void largerArray(){

 Object[] other = new Object[this.array.length*2];

 System.arraycopy(this.array, 0, other, 0, this.array.length);

 this.array = other;

}

 

/**

 * @return true if there are null elements

 */

public boolean isEmpty() {

 boolean bool = true;

 for (Object element : this.array) {

  if(element!=null){

   bool = false;

   break;

  }

  else{

   bool = true;

   break;

 }

 }

 return bool;

}

 

/**

 * Determines the real length of the array

 * @return length of non-null elements

 */

public int size(){

 int count = 0;

 for(int i=0;i<this.array.length;i++){

  if(this.array[i]==null)

   continue;

  else

   count++;

 }

 return count;

}

 

/**

 * Converts array to string.

 * @return the Array as a string

 */

public String toString(){

 String string = "";

 for(int i=0;i<this.size();i++){

  if(i<this.size()-1)

   string += this.array[i]+", ";

  else

   string += this.array[i];

 }

 return string;

}

 

/**

 * Similar to get, imput the character, retrieve index.

 * @param object, what we're looking for

 * @return index

 */

int indexOf(Object object){

 int index = -1;

 for(int i=0;i<this.array.length;i++){

  if(this.array[i]==(object))

   index = i;

  else continue;

 }

 return index;

}

 

/**

 * @param object, Arraylist tyoe

 * @return true, if the elements of the arrays are equivalent.

 */

public boolean equals(ArrayList object){

 boolean bool = false;

 int thisLength = this.array.length;

 int objectLength = object.array.length;

 if(thisLength > objectLength){

  for(int i=0;i<this.array.length;i++)

   if(this.array[i] == object.array[i])

    bool = true;

   else{

    bool = false;

    break;

   }

 }

 else{

  for(int i=0;i<object.array.length;i++)

   if(this.array[i] == object.array[i])

    bool = true;

   else{

    bool = false;

    break;

   }

 }

 return bool;

}

 

/**

 * Getter to check what is at an index

 * @param index, location

 * @return the character at this position

 */

Object get(int index){

 return this.array[index];

}

}

6 0
3 years ago
study the picture of the simulation and the graph above. based on the information obtained from your study of the simulation and
andreyandreev [35.5K]
This is how you know i’m def gonna fail my university class this year :/
6 0
3 years ago
Text that is heavier or darker than other text in the document is considered _____.
kvv77 [185]

The text that is heavier or darker than other text in a document is considered  Bold.

Hope this helped!~

7 0
3 years ago
Read 2 more answers
A photo's color intensity can be modified by changing the brightness and content.
fiasKO [112]
The above statement is FALSE.

A photo's color intensity can be modified by changing the brightness and CONTRAST.

There are four common image controls that makes an image easy to view. These controls are brightness, contrast, saturation, and sharpness.

Brightness control simply brightens the whole image from the shadows to the highlights equally.

Contrast control is the separation between the darkest and brightest areas  of the image.

Saturation control is the separation of colors in the image.

Sharpness control is defined as the edge contrast, meaning the edges in the image are the ones being contrasted.
6 0
3 years ago
What sorts of routine, seemingly unimportant information would help you learn about or break into another company’s network?
tatuchka [14]

Answer and Explanation:

  • Reboot your Computer from which you need to break into.
  • With your remote Ethernet card embedded and the unprotected passageway will mate up in a flash. You likewise need to change the Service Set Identifier (SSID) on your Ethernet card to coordinate SSID on the system's passage. You can decide to physically constrain your DHCP settings to reestablish, however on the off chance that that gives you any trouble.we need to re-boot it.
  • The Third Man ran a sniffer program that caught the majority of the LAN traffic within this organization. It was transmitted through the remote passageway straight into the Third Man's PC. Passwords. Agreements. Email.
4 0
4 years ago
Other questions:
  • ​A(n) ____ will hold an online auction buyer’s payment until he or she is satisfied that the item bought matches the seller’s de
    13·1 answer
  • Generate an array x that has n=100 random numbers that are uniformly distributed over the interval [0,1) . Look up how to use th
    8·1 answer
  • 25 POINTS! PLEASE ANSWER! Karrie would like to draw attention to some short statements in her document. What is the best way to
    6·2 answers
  • The staff of the ___________________ will need to enter, maintain, and retrieve data from electronic health records within a hos
    9·1 answer
  • Suppose the fixed width of an aside element in a fixed layout is 300 pixels, and the fixed width of its parent element (body) is
    15·1 answer
  • An interface does not have ____.
    13·1 answer
  • What major criteria must a product or process meet in order to be considered emerging technology?
    6·1 answer
  • Explain mechanical computer ,electromechanical and electronic computer with example<br>​
    11·1 answer
  • What are the common camera hazards? When might you encounter these hazards in your life, and what do you plan to
    14·1 answer
  • Budgeting for a Computer
    6·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!