For this case we have the following equation of motion:
h (t) = -16t ^ 2 + 90t
Equaling the equation to zero we have:
-16t ^ 2 + 90t = 0
We look for the roots of the polynomial:
(t) (- 16t + 90) = 0
t1 = 0 (initial position)
t2 = 90/16 = 5.625 s (time it reaches the ground again)
Answer:
it will return to the ground in:
t = 5.625 s
Answer:
Range values are:
{-11, 1, 4, 10, 25}
Step-by-step explanation:
Domain values are the possible x values that can be entered into the function, or the inputs. Range values are the y values, or the outputs. By inserting every value in the set into the function, we get the outputs (y values)
-15 + 4 = -11
-3+4 = 1
0 + 4 = 4
6 + 4 = 10
21 + 4 = 25
Remember to put them in order.
Answer:
![y = 4 \\ x = - 2](https://tex.z-dn.net/?f=y%20%3D%204%20%5C%5C%20x%20%3D%20%20-%202)
Step-by-step explanation:
![3(2 - y) + y = - 2 \\ 6 - 2y = - 2 \\ 2y = 8 \\ y = 4 \\ \\ x = 2 - 4 \\ x = - 2](https://tex.z-dn.net/?f=3%282%20-%20y%29%20%2B%20y%20%3D%20%20-%202%20%5C%5C%206%20-%202y%20%3D%20%20-%202%20%5C%5C%202y%20%3D%208%20%5C%5C%20y%20%3D%204%20%5C%5C%20%20%5C%5C%20x%20%3D%202%20-%204%20%5C%5C%20x%20%3D%20%20-%202)
I hope that uesful for u :)
I'm not entirely sure what you're looking for, but here are your options. If you need a perfect square, I'd go for the 12 and 12, but I hope this helps?
it would be 692,000 even though it may look odd since the place holder for 100 is a 0