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3 years ago

At a carnival game, there is a 35% probability of winning a prize. What is the probability of not winning a

Mathematics

2 answers:

Genrish500 [490]3 years ago

8 0

Answer:

There is a 65% probablility of not winning a prize.

Step-by-step explanation:

The 35% chance of winning a prize is taken out of a total percentage of 100. If you subtract 35 from 100, the remaining number, 65, is the probability of not winning, since there are only two possible outcomes.

Svetllana [295]3 years ago

5 0

<h3>Answer: B) 65%</h3>

The two percentages (for winning and not winning) must always add to 100%, which you can think of 100% of a pie. So 100-35 = 65 showing that 35+65 = 100.

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Sarah biked the same distance each day for 6 days. If she traveled 468 kilometers altogether, how many kilometers did she travel

I am Lyosha [343]

76 kilometers per day.

Step by step

468 divided by 6 = 76

76•6=468

8 0

3 years ago

What is -2 = 5 / (2x+3)

LUCKY_DIMON [66]

Answer:

x = -11/4

Step-by-step explanation:

Given that:

-2 = 5 / (2x+3)

Multiplying both sides by (2x + 3)

-2(2x + 3) = 5

"-" sign will alter the inner signs

-4x -6 = 5

Adding 6 on both sides:

-4x -6 +6 = 5 + 6

-4x = 11

Dividing both sides by -4

-4x/-4 = 11/-4

x = -11/4

i hope it will help you!

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3 years ago

A road sign gives drivers information about traffic on busy highways. One sign shows 15 miles in 20 minutes. What is this speed

SIZIF [17.4K]

Answer: Speed in miles per hour is 45 mph.

Step-by-step explanation:

Since we have given that

Distance covered = 15 miles

Time taken to cover the above mentioned distance = 20 minutes

We need to calculate the speed in miles per hour ,

As we know the formula for " Speed " i.e.

$Speed=\frac{Distance}{Time}$

Now, we will put the value of distance and time in the above formula:

$Speed=\frac{15}{20}\times 60\\\\Speed=15\times 3\\\\Speed=45\ mph$

Hence, Speed in miles per hour is 45 mph.

8 0

3 years ago

Read 2 more answers

PLEASE HELP I DO NOT UNDERSTAND AT ALL ITS PRECALC PLEASE SERIOUS ANSWERS

Elina [12.6K]

You want to end up with $A\sin(\omega t+\phi)$ . Expand this using the angle sum identity for sine:

$A\sin(\omega t+\phi)=A\sin(\omega t)\cos\phi+A\cos(\omega t)\sin\phi$

We want this to line up with $2\sin(4\pi t)+5\cos(4\pi t)$ . Right away, we know $\omega=4\pi$ .

We also need to have

$\begin{cases}A\cos\phi=2\\A\sin\phi=5\end{cases}$

Recall that $\sin^2x+\cos^2x=1$ for all $x$ ; this means

$(A\cos\phi)^2+(A\sin\phi)^2=2^2+5^2\implies A^2=29\implies A=\sqrt{29}$

Then

$\begin{cases}\cos\phi=\frac2{\sqrt{29}}\\\sin\phi=\frac5{\sqrt{29}}\end{cases}\implies\tan\phi=\dfrac{\sin\phi}{\cos\phi}=\dfrac52\implies\phi=\tan^{-1}\left(\dfrac52\right)$

So we end up with

$2\sin(4\pi t)+5\cos(4\pi t)=\sqrt{29}\sin\left(4\pi t+\tan^{-1}\left(\dfrac52\right)\right)$

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3 years ago

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Afina-wow [57]

Answer:

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2 years ago