Literal Equations: Solve for g. m + n^2 = g5Q

Simplify 8^6 divided by 8 plssss :/

kolezko [41]

Answer:

Step-by-step explanation:

7 0

3 years ago

Solve the equation: k^2+5k+13=0

mr_godi [17]

Step-by-step explanation:

k² + 5k + 13 = 0

Using the quadratic formula which is

$x = \frac{ - b \pm \sqrt{ {b}^{2} - 4ac } }{2a} \\$

From the question

a = 1 , b = 5 , c = 13

So we have

$k = \frac{ - 5 \pm \sqrt{ {5}^{2} - 4(1)(13) } }{2(1)} \\ = \frac{ - 5 \pm \sqrt{25 - 52} }{2} \\ = \frac{ - 5 \pm \sqrt{ - 27} }{2} \: \: \: \: \: \: \\ = \frac{ - 5 \pm3 \sqrt{3} \: i}{2} \: \: \: \: \: \:$

Separate the solutions

$k_1 = \frac{ - 5 + 3 \sqrt{3} \: i }{2} \: \: \: \: or \\ k_2 = \frac{ - 5 - 3 \sqrt{3} \: i}{2}$

The equation has complex roots

Separate the real and imaginary parts

We have the final answer as

$k_1 = - \frac{5}{2} + \frac{3 \sqrt{3} }{2} \: i \: \: \: \: or \\ k_2 = - \frac{5}{2} - \frac{3 \sqrt{3} }{2} \: i$

Hope this helps you

8 0

2 years ago

Ttm question need help

azamat

Answer:

The first option is the correct answer

Step-by-step explanation:

7 0

3 years ago

What are the zeros of the function below?

Ivan

When you want to find zeros of rational expression you need to find at which points numerator is equal to zero. In this case, we have the product of three expressions.
$x(x-1)(x+11)=0$
A product is equal to zero whenever one of the factors is equal to zero.
That means that zeros of our functions are:
1) $x=0$
2) $x-1=0$
$x=1$
3) $x+11=0$
$x=-11$
The final answer is a. Function has zeros at (0, 1, -11).

3 0

3 years ago

Find the equation of this line. y= [?]x+[?]

DochEvi [55]

Answer:

$y=3x-4$