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3 years ago

6

3

2 answers:

fredd [130]3 years ago

4 0

I think the answer to this is 60

Lyrx [107]3 years ago

4 0

Answer: X= 570

Step-by-step explanation:

X

_____ = 19

15 + 15

Multiply both sides by 30

30X

_____ = 19 x 30

15 + 15

Simplify

x=570

You might be interested in

Provide an appropriate response.

oksian1 [2.3K]

You don't even have to look up the definition of 'standard deviation'. You only
have to remember that 'smaller standard deviation' means 'less spread-out'.

First, let's find the mean (average). It's not supposed to change:

1/7th of (65 + 71 + 77 + 80 + 82 + 90 + 96) = 561/7 = <u>80 and 1/7</u> .

Now, just pick 7 scores that total 561 and are all bunched up.

The easiest way would be 80, 80, 80, 80, 80, 80, 81 .
But that's so easy that it feels like cheating.

Let's say <u>77, 78, 79, 80, 81, 82, and 84</u> .

8 0

2 years ago

Find the angle between the given vectors. Round your answer, in degrees, to two decimal places. u=⟨2,−6⟩u=⟨2,−6⟩, v=⟨4,−7⟩

NISA [10]

Answer:

$\theta = 108.29$

Step-by-step explanation:

Given

$u =$

$v =$

Required:

Calculate the angle between u and v

The angle $\theta$ is calculated as thus:

$cos\theta = \frac{u.v}{|u|.|v|}$

For a vector

$A =$

$A = a * b$

$cos\theta = \frac{u.v}{|u|.|v|}$ becomes

$cos\theta = \frac{.}{|u|.|v|}$

$cos\theta = \frac{2*6+4*-7}{|u|.|v|}$

$cos\theta = \frac{12-28}{|u|.|v|}$

$cos\theta = \frac{-16}{|u|.|v|}$

For a vector

$A =$

$|A| = \sqrt{a^2 + b^2}$

So;

$|u| = \sqrt{2^2 + 6^2}$

$|u| = \sqrt{4 + 36}$

$|u| = \sqrt{40}$

$|v| = \sqrt{4^2+(-7)^2}$

$|v| = \sqrt{16+49}$

$|v| = \sqrt{65}$

So:

$cos\theta = \frac{-16}{|u|.|v|}$

$cos\theta = \frac{-16}{\sqrt{40}*\sqrt{65}}$

$cos\theta = \frac{-16}{\sqrt{2600}}$

$cos\theta = \frac{-16}{\sqrt{100*26}}$

$cos\theta = \frac{-16}{10\sqrt{26}}$

$cos\theta = \frac{-8}{5\sqrt{26}}$

Take arccos of both sides

$\theta = cos^{-1}(\frac{-8}{5\sqrt{26}})$

$\theta = cos^{-1}(\frac{-8}{5 * 5.0990})$

$\theta = cos^{-1}(\frac{-8}{25.495})$

$\theta = cos^{-1}(-0.31378701706)$

$\theta = 108.288386087$

<em></em> $\theta = 108.29$ <em> (approximated)</em>

4 0

2 years ago

what is the approximate percent increase when the population of a town increases from 12,089 to 15,025? round the population amo

IrinaVladis [17]

Answer:

The approximate percentage is 25%.

Step-by-step explanation:

The initial population was = 12089 rounded off to 12000.

The final population is = 15025 rounded off to 15000.

Change in population = $15000-12000=3000$

So, the approximate percent increase is =

$\frac{3000}{12000}\times100$

= 25%.

7 0

3 years ago

Read 2 more answers

A copy machine makes 84 copies in 3 minutes and 30 seconds, how many copies does it make per minute.

matrenka [14]

Answer:

24

Step-by-step explanation:

3 minutes and 30 seconds = 3.5 minutes

84/3.5 = 24copies/minute

4 0

2 years ago

Read 2 more answers

How many ways can five people, a,b,c,d, and e, sit in a row at a movie theater if c must sit to the right of but not necessarily

hichkok12 [17]

A,b,c,d,e
a,b,d,c,e
a,b,d,e,c
b,a,d,e,c
b,d,a,e,c
b,d,e,a,c

7 0

2 years ago

Read 2 more answers