The two richest ecosystems lie in tropical rainforests and coral reefs. On land, tropical rainforests contain many species variation with an abundance of species in bird, mammals, amphibians, and plants. While tropical rainforests occupy only 7 percent of the Earth’s land area, they contain over half of the world’s species. This may be because species richness tends to increase with decreased elevation, increasing solar exposure, and increased precipitation; that is, hot, rainy low-land areas have the most species. In contrast, deserts have low species variation because of low precipitation. On earth, water is majorly important the equation for life. Many of the species are genetically isolated because of habitat size and variation in the build of the land (mountains, equator location, etc) such as seen in the Galapagos islands and the Amazon rainforest, both near and in South America.
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Answer:
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Explanation:</h2><h2 /><h3>There is empirical evidence that environmental injustice is caused by many factors, including discriminatory siting, misguided regulatory policy, unequal regulation enforcement, and unequal political power.</h3>
Going down A-D
Going across is 1-4
A 4
B 3
C 1
D 2
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Answer:
The correct answer would be - MMR would be hindered because both strands would be unmethylated and both would appear as new DNA strands and it would not be able to determine which strand has the error
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Explanation:
In gene expression or DNA replication, the enzyme responsible for the synthesis of DNA from nucleoside triphosphate causes errors sometimes such as mismatch base pair that result in a change in genetic makeup.
For MMR, the DNA template and the strand formed required easily to be differentiated. As the newly synthesized strand is unmethylated and the DNA template strand is methylated results in DNA remain hemimethylated for a very short period.
After MMR, DNA adenine methylase enzyme that transfers a methyl group to the adenine of the sequence 5'-GATC-3' daughter strand formed.
Mutated DAM or DNA adenine methylase will not be able to transfer methyl group which leaves both template and daughter strands unmethylated and mismatch repair would be hindered as it will not be able to identify.
