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2 years ago

Hey can anybody help me with these? thank you!

Mathematics

1 answer:

MissTica2 years ago

8 0

Part 1. I believe the answer to be C. m- 200, b- 0.
Part 2. I think the answer is A. m- 250, b- 2000.
Let me know if i’m correct so others can use this answer.
Good luck

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MARKING YOU BRAINLIST AND 5 STARS! A tire from Karen's car is shown below. Which is the closest to the distance traveled, in fee

Yuki888 [10]

Answer:

18.86 feet

Step-by-step explanation:

One rotation of the tire is equal to the circumference of the tire

The formula for circumference of a circle (remember that a tire is shaped as a circle) = πd

where

π = 22/7

d = diameter

The size of one revolution = 2 x 22/7 = 44/7 feet

The distance covered in one rotation of the tire is 44/7 feet

The distance covered in 3 rotations = (44/7) x 3 = 18.86 feet

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2 years ago

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Answer:

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Step-by-step explanation:

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2 years ago

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Determine the equation of the circle graphed below. ( please help me )

Brums [2.3K]

Answer:

$Equation : \\(x+3)^2 + ( y -2)^2 = 36$

Step-by-step explanation:

For standard form the circle's equation we need the centre of the circle and the radius.

Step 1: Find the centre

If the centre is not given find the end points of the diameter

and then find the mid point.

Let the end points of the diameter be : ( - 3 , 8 ) and ( -3 , -4 )

The mid-point of the diameter is :

$Mid-point = (\frac{-3 + - 3}{2}, \frac{-4+8}{2}) = (-3, 2)$

Therefore, centre of the circle = ( -3 , 2 )

Step 2 : Find radius

$Radius = \frac{Diameter }{2}$

Diameter is the distance between the end points ( -3 , 8) and ( -3 , -4 )

That is ,

$Diameter = \sqrt{(-3-(-3))^2 + ( -4 -8)^2}\\$

$= \sqrt{(-3 + 3)^2 + (-12)^2}\\\\=\sqrt{0 + 144}\\\\=12$

Therefore ,

$Radius = \frac{12}{2} = 6$

Step 3 : Equation of the circle

Standard equation of the circle with centre ( h ,k )

and radius ,r is :

$(x - h)^2+(y -k)^2 = r^2$

Therefore, the equation of the circle with centre ( -3, 2)

and radius = 6 is :

$(x - (-3))^2 + (y - 2)^2 = 6^2\\\\(x + 3)^2 + (y - 2)^2 = 36$

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2 years ago

Determine two pairs of polar coordinates for the point (4, -4) with 0° ≤ θ < 360°.

umka2103 [35]

A polar coordinate is that which can be written as (r, θ) where r is the radius and θ is the angle.

The radius, r, is also the hypotenuse of the right triangle that can be formed. Hence, it can be calculated through the equation,

r² = x² + y²
If we are to simplify this for the r alone, we have,
r = sqrt (x² + y²)

Substituting the known values,
r = sqrt ((4)² + (-4)²) = 4√2

The x and y can be related through the trigonometric function, tangent.
tan θ = y/x
To solve for θ
θ = tan⁻¹(y/x) = tan⁻¹(-4/4) = -45° = 315°

Hence, the polar coordinate is (4√2, 315°)

5 0

3 years ago