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ddd [48]
2 years ago
9

Can anyone help me on this please?

Mathematics
1 answer:
rjkz [21]2 years ago
8 0
\dfrac{4a^3b^2+2a^2b^2+3ab}{ab}=\dfrac{4a^3b^2}{ab}+\dfrac{2a^2b^2}{ab}+\dfrac{3ab}{ab}=4a^2b+2ab+3
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