2 years ago

Can anyone help me on this please?

Mathematics

1 answer:

rjkz [21]2 years ago

8 0

$\dfrac{4a^3b^2+2a^2b^2+3ab}{ab}=\dfrac{4a^3b^2}{ab}+\dfrac{2a^2b^2}{ab}+\dfrac{3ab}{ab}=4a^2b+2ab+3$

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