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slega [8]
3 years ago
5

Write decimal as a fraction in simple form 0.85

Mathematics
1 answer:
jek_recluse [69]3 years ago
3 0

Answer:

17/20

Step-by-step explanation:

0.85 is the same as 85/100 which can be simplified to 17/20 by dividing both the numerator and denominator by 5.

You might be interested in
Geometry, plz help!
astra-53 [7]

Answer:

17. surface area ≈ 441.84

04π m² or  1387.38  m²

18. Ratio of volumes = 8/27

19. volume of the smaller solid = 339 yards³

Step-by-step explanation:

17 .

To find the surface area of the sphere we have to find the radius of the sphere first.

volume of a sphere = 4/3πr³

volume = 1548π m³

r = ?

volume of a sphere = 4/3πr³

1548π = 4/3 × π × r³

multiply both sides by 3/4

1548π × 3/4 = πr³

4644π/4 = πr³

1161π = πr³

divide both sides by π

r³ = 1161

cube root both sides

r = ∛1161

r = 10.5101942

r ≈ 10. 51

surface area of a sphere = 4πr²

surface area = 4 × π × 10.51²

surface area = 4 × 110.4601  × π

surface area = 441.8404π m²  

surface area = 441.8404 × 3.14 = 1387.378856  m² ≈ 1387.38 m²

18

If two figure or solid are similar with scale factor or ratio of x/y then the ratio of their volume is (x/y)³. If the ratio of of two similar prism is 2 : 3 the volume will be (2/3)³ = 8/27 .

19

If two solids are similar then the ratio of their surface area is the squared of the scale factor.

121/361 = (x/y)²

square root both sides

x/y = 11/19

If two solids are similar then the ratio of their volume is the cube of the scale factor.

(11/19)³ = a/1747

1331/6859  = a/1747

cross multiply

6859a = 2325257

divide both sides by 6859

a = 2325257/6859

a = 339.008164455

a ≈ 339 yards³

volume of the smaller solid ≈ 339 yards³

4 0
3 years ago
Use the distributive property to remove the parentheses <br> -5(-4y-w+3)
vampirchik [111]

Answer:

Step-by-step explanation:

Original Equation:

-5(-4y - w + 3)

Multiply -5 by -4y

20y

Multiply -5 by -w

5w

Multiply -5 by 3

-15

Plug these values back into the equation

20y + 5w - 15

Hope this helps :)

6 0
3 years ago
The student council set a goal of raising at least $500 in flower sales. So far it has raised $415. Write an inequality to show
sergij07 [2.7K]
$500 < or = $415 + d

(subtract the 415 from both sides)

$85 < or = d
3 0
3 years ago
Hiiio!❤️ Could someone please help me with this question!❤️❤️❤️
Aneli [31]

Answer:

What question

Step-by-step explanation:

3 0
2 years ago
Seventy percent of all vehicles examined at a certain emissions inspection station pass the inspection. Assuming that successive
NeX [460]

Answer:

(a) 0.343

(b) 0.657

(c) 0.189

(d) 0.216

(e) 0.353

Step-by-step explanation:

Let P(a vehicle passing the test) = p

                        p = \frac{70}{100} = 0.7  

Let P(a vehicle not passing the test) = q

                         q = 1 - p

                         q = 1 - 0.7 = 0.3

(a) P(all of the next three vehicles inspected pass) = P(ppp)

                           = 0.7 × 0.7 × 0.7

                           = 0.343

(b) P(at least one of the next three inspected fails) = P(qpp or qqp or pqp or pqq or ppq or qpq or qqq)

      = (0.3 × 0.7 × 0.7) + (0.3 × 0.3 × 0.7) + (0.7 × 0.3 × 0.7) + (0.7 × 0.3 × 0.3) + (0.7 × 0.7 × 0.3) + (0.3 × 0.7 × 0.3) + (0.3 × 0.3 × 0.3)

      = 0.147 + 0.063 + 0.147 + 0.063 + 0.147 + 0.063 + 0.027

      = 0.657

(c) P(exactly one of the next three inspected passes) = P(pqq or qpq or qqp)

                 =  (0.7 × 0.3 × 0.3) + (0.3 × 0.7 × 0.3) + (0.3 × 0.3 × 0.7)

                 = 0.063 + 0.063 + 0.063

                 = 0.189

(d) P(at most one of the next three vehicles inspected passes) = P(pqq or qpq or qqp or qqq)

                 =  (0.7 × 0.3 × 0.3) + (0.3 × 0.7 × 0.3) + (0.3 × 0.3 × 0.7) + (0.3 × 0.3 × 0.3)

                 = 0.063 + 0.063 + 0.063 + 0.027

                 = 0.216

(e) Given that at least one of the next 3 vehicles passes inspection, what is the probability that all 3 pass (a conditional probability)?

P(at least one of the next three vehicles inspected passes) = P(ppp or ppq or pqp or qpp or pqq or qpq or qqp)

=  (0.7 × 0.7 × 0.7) + (0.7 × 0.7 × 0.3) + (0.7 × 0.3 × 0.7) + (0.3 × 0.7 × 0.7) + (0.7 × 0.3 × 0.3) + (0.3 × 0.7 × 0.3) + (0.3 × 0.3 × 0.7)

= 0.343 + 0.147 + 0.147 + 0.147 + 0.063 + 0.063 + 0.063

                  = 0.973  

With the condition that at least one of the next 3 vehicles passes inspection, the probability that all 3 pass is,

                         = \frac{P(all\ of\ the\ next\ three\ vehicles\ inspected\ pass)}{P(at\ least\ one\ of\ the\ next\ three\ vehicles\ inspected\ passes)}

                         = \frac{0.343}{0.973}

                         = 0.353

3 0
3 years ago
Read 2 more answers
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