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ivann1987 [24]
3 years ago
5

6r-r + 8(15-r)+23-6 is it equivalent to 3r+137

Mathematics
2 answers:
natita [175]3 years ago
7 0

Answer:

No, it's not equivalent

Step-by-step explanation:

Try and solve the one with the bracket first. Expand 8(15-r) : 8x15 and 8x-r = 120 - 8r

Therefore, the equation can now be written as:

6r-r + 120-8r + 23-6

Rearrange the like terms together and solve the equation:

6r-r-8r + 120+23-6 = -3r + 137

gizmo_the_mogwai [7]3 years ago
6 0

Answer:This is not an equation and it would never be one

Step-by-step explanation:

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HELP!! I only need the answer. Thank you!
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The answer would be 6 3/8

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Let f(x) = -2x + 4 and g(x) = 5x - 7. Find f(x) - g(x).
balandron [24]

Answer:

If you are just looking for a simplified answer then the answer is -7x - 3.

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Math help!! This is really difficult​
Reptile [31]

Answer:

y = -3/2 x +13

Step-by-step explanation:

We want our line to be perpendicular to

y = 2/3 x -1

The slope of this line is 2/3   (since it is written in the form y = mx+b and m is the slope)

Perpendicular lines have negative reciprocal slopes

m = -(3/2)

The slope of our new line is -3/2

We can use point slope form of the equation

y-y1 - m (x-x1)

y - 7 = -3/2 (x-4)

Distribute

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4 0
3 years ago
PLEASE HELP! WILL GIVE 70 POINTS!!
Tresset [83]

Answer:

A=189\ mm^2

Step-by-step explanation:

<u>Surface Areas </u>

Is the sum of all the lateral areas of a given solid. We need to compute the total surface area of the given prism. It has 5 sides, two of them are equal (top and bottom areas) and the rest are rectangles.

Computing the top and bottom areas. They form a right triangle whose legs are 4.5 mm and 6 mm. The area of both triangles is

\displaystyle A_t=2*\frac{b.h}{2}=b.h=(4.5)(6)=27 mm^2

The front area is a rectangle of dimensions 7.7 mm and 9 mm, thus

A_f=b.h=(7.5)(9)=67.5 \ mm^2

The back left area is another rectangle of 4.5 mm by 9 mm

A_l=b.h=(4.5)(9)=40.5  \ mm^2

Finally, the back right area is a rectangle of 6 mm by 9 mm

A_r=b.h=(6)(9)=54 \ mm^2

Thus, the total surface area of the prism is

A=A_t+A_f+A_l+A_r=27+67.5+40.5+54=189\ mm^2

\boxed{A=189\ mm^2}

4 0
3 years ago
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