Question

The sum of three consecutive integers is 144. What is the smallest of these integers?

Answer 1

Answer:

They are 46, 48, 50.

Step-by-step explanation:

An even number is a multiple of

2

, then can be written as 2n. The next even number after

2

n

is

2

n

+

2

and the following is

2

n

+

4

.

So you are asking for which value of

n

it you have

(

2

n

)

+

(

2

n

+

2

)

+

(

2

n

+

4

)

=

144

I solve it for

n

6

n

+

6

=

144

n

=

138

6

=

23

.

The three numbers are

2

n

=

2

⋅

23

=

46

2

n

+

2

=

46

+

2

=

48

2

n

+

4

=

46

+

4

=

50