The sum of three consecutive integers is 144. What is the smallest of these integers?
1 answer:
Answer:
They are 46, 48, 50.
Step-by-step explanation:
An even number is a multiple of
2
, then can be written as 2n. The next even number after
2
n
is
2
n
+
2
and the following is
2
n
+
4
.
So you are asking for which value of
n
it you have
(
2
n
)
+
(
2
n
+
2
)
+
(
2
n
+
4
)
=
144
I solve it for
n
6
n
+
6
=
144
n
=
138
6
=
23
.
The three numbers are
2
n
=
2
⋅
23
=
46
2
n
+
2
=
46
+
2
=
48
2
n
+
4
=
46
+
4
=
50
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