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Vlad1618 [11]
3 years ago
9

Help me out with this and ill give brainliest

Mathematics
1 answer:
Zanzabum3 years ago
6 0

Answer:

135

260

410

Step-by-step explanation:

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I need help with this question
bearhunter [10]

Answer:

  7.28 miles

Step-by-step explanation:

Suppose the distance at closest approach is represented by x. Then the distance to the point of closest approach at the first sighting is ...

  d1 = x·tan(62°)

At the second sighting, the distance to the point of closest approach is ...

  d2 = x·tan(38°)

The difference of these distances is 8 miles, so we have ...

  d1 -d2 = 8 = x(tan(62°) -tan(38°))

Dividing by the coefficient of x, we find ...

  x = 8/(tan(62°) -tan(38°)) ≈ 7.2764 . . . . miles

The point of closest approach is about 7.28 miles from the landmark.

5 0
3 years ago
HELP FASTTTT
UkoKoshka [18]

The line plot illustrates the capacity of the kitchen sink in gallons, and it has a sample size is 21. The distribution is positively skewed, with an appropriate measure of center is 16 and an appropriate measure of spread is 2.5

<h3>The description of the data</h3>

The dataset on the line plot represents the capacity of the kitchen sink.

The capacities are measured in gallons

<h3>The number of data values</h3>

This is the number of dots on the line plot.

There are 21 dots on the plot

Hence, the number of data values is 21

<h3>The shape of the distribution</h3>

The shape of the given distribution is positively skewed.

This is so because there are more points on the left of the distribution

<h3>Appropriate measure of center</h3>

The median is the appropriate measure of center for a skewed distribution.

So, we simply calculate the median.

The median position is calculated using

Median = 0.5 *  (n + 1) th

So, we have:

Median = 0.5 *  (21 + 1) th

Median = 11th

The 11th data element is 16

Hence, the value of an appropriate measure of center is 16

<h3>Appropriate measure of spread</h3>

The IQR is the appropriate measure of spread for a skewed distribution.

The IQR is:

IQR = Q3 – Q1

Where:

Q3 = 0.75(n + 1)th and  Q1 = 0.25(n + 1)th

This gives

Q3 = 0.75 * (21 + 1)th = 16.5

Q1 = 0.25(21 + 1)th = 5.5

The 16.5th element is 17.5, while the 5.5th element is 15

Recall that:

IQR = Q3 – Q1

So, we have:

IQR = 17.5 - 15

Evaluate

IQR = 2.5

Hence, the value of an appropriate measure of spread is 2.5

Read more about line plots at:

brainly.com/question/27246403

#SPJ1

8 0
2 years ago
The area of a square patio is 49^3 square inches. find the length of one side of the patio. Please show work.
Hatshy [7]
A = l × w
So, first you solve 49^3 and get 117,649 square inches. Then you divide that by 2 and get 58,824.5, because 58,824.5 × 2 is 117,649.

Your answer is: one patio side length is 58,824.5 inches long
3 0
3 years ago
Read 2 more answers
Uhm pls help me rn i need help
Setler [38]

Answer:

hey i would help you but i cant because my school computer blocked the image

Step-by-step explanation:

if you could tell me text wise i might be able to help you out :)

7 0
4 years ago
How do I solve <br> PV = nRT for T
Svetlanka [38]

Answer:

PV+=+nRT divide both sides by nR

PV/NR

Step-by-step explanation:

6 0
4 years ago
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