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3 years ago

15

If two polygons are similar then the corresponding sides must be?

2 answers:

dlinn [17]3 years ago

6 0

Answer:

if two polygons are similar then the sides are congruent

Maslowich3 years ago

4 0

Answer:

Two polygons are similar if their corresponding angles are congruent and the corresponding sides have a constant ratio (in other words, if they are proportional).

Step-by-step explanation:

(plz like and follow if this helps:)

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The fountain is made up of two semicircles and a quarter circle. Find the perimeter and the area of the fountain. Round the peri

Andrej [43]

FOUND THE COMPLETE QUESTION IN ANOTHER SOURCE.ATTACHED IMAGE.
For this case what we have is the following:
For the two semicircles we can model it as a complete circle.
We have to then:

Perimeter:
P = 2 * pi * r
or
P = pi * d
Where,
r = radius
d = diameter
Therefore the perimeter is:
P = 10 * pi
For the largest circle we have:
radius = 10
Perimeter:
P '= 2pi10
P '= 20pi
1/4 since 1/4 circle:
P '' = 20pi / 4 = 5pi
Then, the total perimeter of the source is:
Pt = P + P '' = 10pi + 5pi = 15pi
Pt = 15 * (3.141592)
Pt = 47.1239
round
Pt = 47.1 ft

Area:
The total area will be:
A = A (two semicircles) + A (quarter big circle)
A = (pi / 4) * (d ^ 2) + (1/4) * pi * r ^ 2
A = (pi / 4) * ((10) ^ 2) + (1/4) * pi * (5) ^ 2
A = 98.17477042 feet ^ 2
Round:
A = 98.2 feet ^ 2

Answer:
Perimeter of the source:
Pt = 47.1 ft
Area of the source:
A = 98.2 feet ^ 2

5 0

2 years ago

Paisley drove to his new college and then came back home. His round trip was 212 miles. Paisley drives a Honda and gets 35 miles

san4es73 [151]

Answer:

because of this the awnser

7 0

2 years ago

The number of accidents that occur at a busy intersection is Poisson distributed with a mean of 4.5 per week. Find the probabili

Mariana [72]

Answer:

a) 0.01111

b) 0.4679

c) 0.33747

Step-by-step explanation:

We are given the following in the question:

The number of accidents per week can be treated as a Poisson distribution.

Mean number of accidents per week = 4.5

$\lambda= 4.5$

Formula:

$P(X =k) = \displaystyle\frac{\lambda^k e^{-\lambda}}{k!}\\\\ \lambda \text{ is the mean of the distribution}$

a) No accidents occur in one week.

$P(x =0)\\\\= \displaystyle\frac{4.5^0 e^{-4.5}}{0!}= 0.01111$

b) 5 or more accidents occur in a week.

$P( x \geq 5) = 1-\displaystyle \sum P(x$

c) One accident occurs today.

The mean number of accidents per day is given by

$\lambda = \dfrac{4.5}{7} = 0.64$

$P(x =1)\\\\= \displaystyle\frac{0.64^1 e^{-0.64}}{1!}= 0.33747$

5 0

2 years ago

Three times a number plus 12 minus 5 times the same number is 22. what is the number?

saw5 [17]

3n+12-5 x n=22

4n=15

4 0

3 years ago

Read 2 more answers

Approximately how long is a leg of an isosceles right triangle that has a hypotenuse of length 11.31

Lapatulllka [165]

Answer:

Leg of an isosceles right triangle is 7.99 long.

Step-by-step explanation:

Given:

Length of the hypotenuse =11.31

To find:

Length of the leg of an isosceles right triangle =?

Solution:

According to Pythagorean's Theorem, we have

$a^2 +b^2 = c^2$ -----------------------------(1)

Here were are given as isosceles triangle, so the two sides will be of same length

So equation 1 can be rewritten as

$a^2 +a^2 = c^2$

$2a^2 = c^2$

Substituting the value of hypotenuse

$2a^2 = (11.31)^2$

$2a^2 = 127.91$

$a^2 = \frac{127.91}{2}$

$a^2 =63.955$

$a = \sqrt{63.955}$

a = 7.99

7 0

2 years ago