Given: AABC, m_ACB=90°, CD 1 AB, m ZACD=60º, BC = 6 cm Find: CD, Area of AABC
1 answer:
Answer:
Look below
Step-by-step explanation:
Given that CDB is 90 degrees, ACB is 90 degrees, and ACD is 60 degrees, we can determine that DCB = 90-60 = 30 degrees.
This means triangle BCD is a 30-60-90 (angle measures) right triangle
The proportions of the sides (from smallest to largest) is
x:x√3:2x
We are given that BC = 6 cm. This means...
2x=6
x=3
This means DB is 3 cm and CD is 3√3 cm
Using the linear pair theorem, we can find that Angle CDA is 90 degrees. This means ACD is also a 30-60-90 triangle.
x=3√3
x√3=9
2x=6√3
Now we need to find AB
AB = AD + DB
AB = 9 + 3
AB = 12 cm
You might be interested in
I hope it can help you
Answer:
Perimeter of rectangle before folded = 56 in
Total area after folding = 156 sq in
Step-by-step explanation:
Rectangle before folded: l = 16 and w = 12
P = 2(16) + 2(12) = 32 + 24 = 56 in.
Figure after folding: Area of trapezoid + area of rectangle
Area of trapezoid = h()/2 = 6(4 + 16)/2 = 60
Area of rectangle = lw = 16(6) = 96
Total area after folding = 60 + 96 = 156 sq in.
Note: You could also find the area after folding by substracting the areas of the two triangles in the corners from the area of the original rectangle. Your choice. OK?