Question

The surface of a hill is modeled by z = 100 − 4 x 2 − 2 y 2 . When a group of hikers reach the point (-3,-2,56) it begins to snow. They decide to descend the hill as rapidly as possible. Which of the following vectors points in the direction they should start their descent? < 24 , 8 > < 24 x , 8 y > < − 24 x , − 8 y > < − 24 , − 8 > None of the above

Answer 1

Answer:

(-24, -8)

Step-by-step explanation:

Let us recall that when we have a function f

$\large f:\mathbb{R}^2\rightarrow \mathbb{R}\\f(x,y)=z$

if the gradient of f at a given point (x,y) exists, then the gradient of f at this point (x,y) gives the direction of maximum rate of increasing and minus the gradient of f at this point gives the direction of maximum rate of decreasing. That is

$\large \nabla f=(\frac{\partial f}{\partial x},\frac{\partial f}{\partial y})$

at the point (x,y) gives the direction of maximum rate of increasing

$\large -\nabla f$

at the point (x,y) gives the direction of maximum rate of decreasing

In this case we have

$\large f(x,y)=100-4x^2-2y^2$

and we want to find the direction of fastest speed of decreasing at the point (-3,-2)

$\large \nabla f(x,y)=(-8x,-4y) \Rightarrow -\nabla f=(8x,4y)$

at the point (-3,-2) minus the gradient equals

$\large -\nabla f(-3,-2)=(-24,-8)$

hence the vector (-24,-8) points in the direction with the greatest rate of decreasing, and they should start their descent in that direction.