It would be -70. Your welcome
Answer:
Step-by-step explanation:
the base of the vase will be where the vase touches the x-axis, that is 10 cm, therefore, the base is 10 cm from the wall
:
b) 25 = x^2 -20x +100, we solve for x to find the closest distance since as we move up the vase the distance to the wall gets closer(assume the y-axis is the wall), then
x^2 -20x +75 = 0 (x-15) * (x-5) = 0
x = 15 and x = 5
we reject x = 15
the shortest distance from the top of the vase to the wall is 5 cm
:
c) this is a left shift of the equation y = (x-10)^2
from b) we know that the left shift is 5 cm
10 - 5 = 5 cm from the wall to the base
:
d) y = (x-10+5)^2
y = (x-5)^2
Answer:
B
Step-by-step explanation:
That would be c
x could be any real number.
Answer:
6
Step-by-step explanation:
But not too sure tho make sure of it
