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saul85 [17]
3 years ago
12

Nine more than a number is eleven

Mathematics
1 answer:
bearhunter [10]3 years ago
5 0

Answer:

Step-by-step explanation:

nine more then a number is eleven

let the number be n

n + 9 = 11 <=== ur equation

n = 11 - 9

n = 2

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Answer:

(8.5)

Step-by-step explanation:

Just add the 2 numbers

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3 years ago
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<E=<G=115°

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3 years ago
Helppppp plssss I’m not tryna fail math !!!
VARVARA [1.3K]

Answer:

1.25*10^-4

2*10^-4

3.25*10^-10

Step-by-step explanation:

6 0
3 years ago
Read 2 more answers
NEED HELP
Studentka2010 [4]
First use distributive property on both sides of the equation.
-9(-16 - f) = 4(1 - 3f)
144 + 9f = 4 - 12f
Then isolate f on one side of the equation:
3f = -140
f = 46.67 --> (which is equal to -140/3)
I'm sorry I couldn't help more. I don't know why it's wrong. Maybe try putting in it decial form instead.
6 0
3 years ago
PLEASE HELP
Anit [1.1K]

Answer:

A\approx2.255 \text{ grams}

Step-by-step explanation:

We will use the standard formula for half-life:  

\displaystyle A=A_0(a)^\frac{t}{d}

Where A₀ is the initial amount, a is the half-life, d is the time for one half-life, and t is the number of days.

So, we will substitute 1/2 for a and 24.3 for d. This yields:

\displaystyle A=A_0(\frac{1}{2})^\frac{t}{24.3}

We have a 3 gram sample. Therefore, our initial amount A₀ is 3:

\displaystyle A=(3)(\frac{1}{2})^\frac{t}{24.3}

And we want to find the remaining sample after 10 days. So, t=10. Substitute:

\displaystyle A=(3)(\frac{1}{2})^\frac{10}{24.3}

Use a calculator. So:

A\approx2.255 \text{ grams}

Therefore, for a 3 gram sample of Phosphorous-32 with a half-life of 24.3 days, after 10 days, there will be approximately 2.255 grams remaining.

6 0
3 years ago
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