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3 years ago

Identify the correct way to the nearest 1/8 pound

Mathematics

1 answer:

igomit [66]3 years ago

3 0

Answer:

2 4/16 = 2 1/4 lb

Step-by-step explanation:

The pointer is 4 of the smallest units above 2. There are 16 of those small units. Each 2 of those units is 1/8 pound, so when the pointer is on a multiple of 2 units, it is on a multiple of 1/8 pound. No guesswork is required to choose the correct weight to the nearest 1/8 pound.

2 4/16 = 2 1/4 lb . . . . the scale reading to the nearest 1/8 pound.

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gavmur [86]

Answer:

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Step-by-step explanation:

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3 years ago

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If 3 times a square of an integer is added to 1 times the integer, the result is 2

jarptica [38.1K]

Let unknown integer be n.

So then your sentence would translate to 3n² + n = 2.

If you need to solve for n then we can move 2 to left side by subtract both sides by 2:

3n² + n - 2 = 0

Now you can factor:

3n² + 3n -2n - 2 = 0

3n( n + 1 ) - 2( n + 1 ) = 0

( 3n - 2 )( n + 1 ) = 0

3n - 2 = 0 OR n + 1 = 0

3n = 2 OR n = -1

n = 2/3 OR n = -1

Final answer: n = 2/3 OR n = -1

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3 years ago

If we inscribe a circle such that it is touching all six corners of a regular hexagon of side 10 inches, what is the area of the

Brrunno [24]

Answer:

$\left(100\pi - 150\sqrt{3}\right)$ square inches.

Step-by-step explanation:

<h3>Area of the Inscribed Hexagon</h3>

Refer to the first diagram attached. This inscribed regular hexagon can be split into six equilateral triangles. The length of each side of these triangle will be $10$ inches (same as the length of each side of the regular hexagon.)

Refer to the second attachment for one of these equilateral triangles.

Let segment $\sf CH$ be a height on side $\sf AB$ . Since this triangle is equilateral, the size of each internal angle will be $\sf 60^\circ$ . The length of segment

$\displaystyle 10\, \sin\left(60^\circ\right) = 10 \times \frac{\sqrt{3}}{2} = 5\sqrt{3}$ .

The area (in square inches) of this equilateral triangle will be:

$\begin{aligned}&\frac{1}{2} \times \text{Base} \times\text{Height} \\ &= \frac{1}{2} \times 10 \times 5\sqrt{3}= 25\sqrt{3} \end{aligned}$ .

Note that the inscribed hexagon in this question is made up of six equilateral triangles like this one. Therefore, the area (in square inches) of this hexagon will be:

$\displaystyle 6 \times 25\sqrt{3} = 150\sqrt{3}$ .

<h3>Area of of the circle that is not covered</h3>

Refer to the first diagram. The length of each side of these equilateral triangles is the same as the radius of the circle. Since the length of one such side is $10$ inches, the radius of this circle will also be $10$ inches.

The area (in square inches) of a circle of radius $10$ inches is:

$\pi \times (\text{radius})^2 = \pi \times 10^2 = 100\pi$ .

The area (in square inches) of the circle that the hexagon did not cover would be:

$\begin{aligned}&\text{Area of circle} - \text{Area of hexagon} \\ &= 100\pi - 150\sqrt{3}\end{aligned}$ .

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3 years ago

A baker made 35 pastries in 3 1/2 hours. how many pastries dod the baker make in one hour?

Sophie [7]

Answer:

10 pastries

Step-by-step explanation:

To find how many they made in 1 hour, divide 35 by 3 1/2

35/3.5

= 10

So, he made 10 pastries in 1 hour

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3 years ago

nadezda [96]

Answer:

4 i think or -5 +1.........

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3 years ago

Identify the correct way to the nearest 1/8 pound​

Identify the correct way to the nearest 1/8 pound