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2 years ago

Find the equivalent exponential expression. (7^4)^5

Mathematics

2 answers:

Murrr4er [49]2 years ago

8 0

To solve this, we need to know a formula. The formula is:

$(x^{y} )^{z} = (x^{yz})$

That being said, now we can simplify. $(7^{4} )^{5} = (7^{4*5})$ =
$7^{20}$

Nikolay [14]2 years ago

6 0

Hi!

To solve exponental equations, multiply the exponents.
4·5=20

The answer is $7^{20}$

Hope this helps! :)
-Peredhel

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2 years ago

What are the solutions of x2 = 8 – 5x? startfraction 5 minus startroot 57 endroot over 2 endfraction comma startfraction 5 start

kondor19780726 [428]

The solution of the given quadratic equation are,

$x=\frac{-5-\sqrt{57} }{2}$ , $x=\frac{-5+\sqrt{57} }{2}$

The equation to solve is given as

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Rearrange the given equation in standard form, $ax^2+bx+c=0$

where, a,b and c are constants.

Therefore, we add 5x-8 on both sides to get,

$x^2+5x-8=0$

Here, a=1,b=5 and c=-8

The solution to the above equation is

<h3>What is the quadratic formula?</h3>

$x=\frac{-b\±\sqrt{b^2-4ac} }{2a}$

Use the value of a,b,c in the quadratic formula and solve for x

$x=\frac{-5\±\sqrt{5^2-4(1)(-5)} }{2(1)}$

$x=\frac{-5\±\sqrt{25+35} }{2(1)}$

$x=\frac{-5\±\sqrt{57} }{2(1)}$

Therefore, the solutions are

$x=\frac{-5-\sqrt{57} }{2},x=\frac{-5+\sqrt{57} }{2}$

To learn more about the quadratic equation visit:

brainly.com/question/25841119

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2 years ago

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