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lesya [120]
3 years ago
10

How do i find the weight

Mathematics
1 answer:
Alla [95]3 years ago
4 0
Convert it then you will fine the weight.
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Solve. T + 23 > 1 t > 24 t > –22 t < 24 t < –22
creativ13 [48]

t + 23 > 1     subtract 23 from both sides

t + 23 - 23 > 1 - 23

t > -22

5 0
3 years ago
Solve for x: 2x^5/3-22=464 a) x = 28 b) x = 27 c) x = ±27 d) x = ±28
Effectus [21]

Answer:

<h3>x = 27</h3>

Step-by-step explanation:

Given the expression {2x^{\frac{5}{3} }-22 = 464, we are to find the value of x in the expression. This is as shown below;

{2x^{\frac{5}{3} }-22 = 464

add 22 to both sides

{2x^{\frac{5}{3} }-22 = 464+22\\\\

{2x^{5/3} =486

divide both sides by 2

\frac{2x^{5/3}}{2} =\frac{486}{2}\\ x^{5/3} = 243

raise both sides to the power of 3/5

(x^{5/3})^{3/5} = (243)^{3/5}\\x = (\sqrt[5]{243}) ^3\\x = 3^3\\x = 27

Hence the value of x is 27

8 0
3 years ago
Use the zero product property to find the solutions to the equation 2x2 + x-1 = 2
algol [13]

Answer:

see explanation

Step-by-step explanation:

Given

2x² + x - 1 = 2 ( subtract 2 from both sides )

2x² + x - 3 = 0

Consider the factors of the product of the coefficient of the x² term and the constant term which sum to give the coefficient of the x- term

product = 2 × - 3 = - 6 and sum = + 1

The factors are - 2 and + 3

Use these factors to split the x- term

2x² - 2x + 3x - 3 = 0 ( factor the first/second and third/fourth terms )

2x(x - 1) + 3(x - 1) = 0 ← factor out (x - 1) from each term

(x - 1)(2x + 3) = 0

Equate each factor to zero and solve for x

x - 1 = 0 ⇒ x = 1

2x + 3 = 0 ⇒ 2x = - 3 ⇒ x = - \frac{3}{2}

3 0
3 years ago
Read 2 more answers
If you have three cups of pineapple Juice How many total cups of Punch Can you make
Mama L [17]

Answer: 2 cups


Step-by-step explanation:


5 0
3 years ago
Point M is located at (3,7). If point M is translated 2 units to the left and 4 units down, what are the coordinates of M Q1 (-1
Natasha_Volkova [10]
The answer is simply (1,3) just subtract 2 from 3 and 4 from 7.
3 0
3 years ago
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