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artcher [175]
2 years ago
13

What is the inequality for the range of the value of x

Mathematics
1 answer:
Vilka [71]2 years ago
5 0

Answer:

4x - 5 < x + 1 is an inequality because the solution to the equation is a range of values of x. You can find the range of values of x, by solving the inequality as if it was a normal equation. (This means that when the value of x is less than 2, the inequality 4x - 5 < x + 1 is true.)

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the graph below shows the cost of tomato plants for each plant purchased. What is the cost of one tomato plant.​
dem82 [27]

Answer:

2.50

Step-by-step explanation:

6 0
3 years ago
Read 2 more answers
Find the slope for numbers 1-6
Helga [31]

Answer:

#1 is 2

#2 is -2/3

#3 is -2/5

#4 is -1/2

#5 is 4

#6 is 1

Step-by-step explanation:

I hope this helps

4 0
3 years ago
Use the definitions for the sets given below to determine whether each statement is true or false:
ella [17]

Answer:

(a) false

(b) true

(c) true

(d) true

(e) false

(f) true

(g) false

(h) true

(i) true

Step-by-step explanation:

(a) 15 ⊂ A, since 15 is not a set, but an element, we cannot say of an element to be subset of a set. False

(b) {15} ⊂ A The subset {15} is a subset of A, since every element of {15}, that is 15, belongs to A.

15 ∈ {15} and 15 ∈ { x ∈ Z: x is an integer multiple of 3 } 15 is  an integer multiple of 3. since 15/3=5. True

(c)∅ ⊂ A

∅ is a subset of any set. True

(d) A ⊆ A

A is a subset of itself. True

(e)∅ ∈ B

∅ is not an element, it is a subset, so it does not belong to any set. False

(f)A is an infinite set.

Yes, there are infinite integers multiple of 3. True

(g)B is a finite set.

No, there are infinite integers that are perfect squares. False

(h)|E| = 3

The number of elements that belong to E are 3. True

(i)|E| = |F|

The number of elements that belong to F are 3. So is the number of elements of E. True

7 0
3 years ago
Two less than a number cubed<br><br>múltiple choices<br>2−x³<br><br>x² - 3<br><br>x³- 2<br><br>3-x²​
ella [17]

The first one (2-x^3) is the correct one

5 0
2 years ago
A company with offices in Anchorage, Alaska wants to lease 10 small planes to fly a group of clients to Nome for a summer fishin
Rama09 [41]

The solutions of the equations of the situation can be:

z = 1 , y = 5, x = 4

z= 2 , y = 3, x = 5

z=3 , y = 1, x = 6

z = 0 , y = 7, x =3

The question can be expressed as a equation

6 x + 8 y + 10 z = 84

also, x + y + z = 10

⇒ x = 10- y - z

Putting it in first equation,

6(10 - y - z ) +8y + 10z = 84

⇒ 60 +2y + 4z = 84

⇒2(y + 2z ) = 14

⇒ y + 2z = 7

Now putting

z = 1 , we get y = 5,

z= 2 , y = 3

z=3 , y = 1

z = 0 , y = 7

So, only 4 possible solutions.

Therefore, there can only be 4 possible solutions for the equations.

"Learn more about linear equation here-

brainly.com/question/28442870 "

#SPJ9

8 0
11 months ago
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