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Arisa [49]
3 years ago
14

Choose all sets that contain the number 5.

Mathematics
1 answer:
s344n2d4d5 [400]3 years ago
8 0
This should be the correct answer

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Which of the following illustrates the truth value of the given mathematical statements? 6 + 3 = 9, and 4 • 4 = 16
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I mean, they both do. i am not 100% sure, but im pretty sure. Hope this helps!
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A rental car agency charges $240 per week plus 0.25 per miles to my car how many miles can you travel in one week for 432.50​
nataly862011 [7]
432.5-240= 192.50

192.50/.25=770miles
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The fraction 4/6 could represent the green

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I just need to know which expressions are equal to the given one at the top. I will award brainliest for the best and correct an
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The last choice is one.

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3 years ago
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A corporation must appoint a​ president, chief executive officer​ (CEO), chief operating officer​ (COO), and chief financial off
Yakvenalex [24]

Answer:

a) The officers can be appointed in 24024 different ways.

b) The committee can be appointed in 1001 different ways.

c) 1.1% probability of randomly selecting the committee members and getting the three youngest of the qualified​ candidates

Step-by-step explanation:

The order in which the officers are appointed is important(the first is the president, second the CEO and so on...). So the permutations formula will be used.

Otherwise, in the committee there are no roles, so the order is not important. So the combinations formula will be used.

Permutations formula:

The number of possible permutations of x elements from a set of n elements is given by the following formula:

P_{(n,x)} = \frac{n!}{(n-x)!}

Combinations formula:

C_{n,x} is the number of different combinations of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

A. How many different ways can the officers be ​appointed?

4 from a set of 14, with roles. So a permutation.

P_{(14,4)} = \frac{14!}{(14-4)!} = 24024

The officers can be appointed in 24024 different ways.

B. How many different ways can the committee be​ appointed?

4 from a set of 14, without roles. So combination

C_{14,4} = \frac{14!}{4!(14-4)!} = 1001

The committee can be appointed in 1001 different ways.

C. What is the probability of randomly selecting the committee members and getting the three youngest of the qualified​ candidates?

A probability is the number of desired outcomes divided by the number of total outcomes.

Desired outcomes.

The three youngest(1 combination), and one of the other 14-3 = 11. So D = 1*11 = 11

Total outcomes:

From B., 1001, so T = 1001

Probability:

p = \frac{D}{T} = \frac{11}{1001} = 0.011

1.1% probability of randomly selecting the committee members and getting the three youngest of the qualified​ candidates

8 0
3 years ago
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