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olga55 [171]
2 years ago
14

A farmer has 220 bushels of beans for sale at a​ farmer's market. He sells an average of 16 and three fourths bushels each day.

After 6 ​days, what is the change in the total number of bushels the farmer has for sale at the​ farmer's market?
Mathematics
1 answer:
Artist 52 [7]2 years ago
6 0

Answer:

The answer is= 119 Bushels and a half(119.5)

Step-by-step explanation:

Equation related to the problem= 220-(67/4)·T=bushels of Beans left

After 6 days=

220-(67/4·)6=bushels of Beans left

Bushels of beans left=119.5---> You need to change the dot for a fraction

119.5 is 119 bushes and a half so

The answer is= 119 Bushels and a half(119.5)

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3 0
3 years ago
A new car is purchased for 23700 dollars. The value of the car depreciates at
mojhsa [17]

The value of the car after 10 years is $5557.8.

What is depreciation?

Depreciation refers to the reduction in the value of an asset over time and such valued reductions are reflected in the Balance sheet at the year ended.

Given

A new car is purchased for 23700 dollars.

The value of the car depreciates at 13.5% per year.

According to the question,

The value of the car depreciates therefore the amount of the car is determined by the formula,

Where, P = $23700, r = 13.5% and t =10 years

Substitute all the values in the formula,

Hence, the value of the car after 10 years is $5557.8.

To know more about Percentages click the link given below.

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8 0
2 years ago
If a laptop computer regularly costs $979 and is on sale for $679, what percentage discount is being given? Round your answer to
Lady_Fox [76]

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4 0
2 years ago
Read 2 more answers
Consider the spreading of a rumor through a company of 1000 employees, allworking in the same building.We assume that the spread
natima [27]

Answer:

On the 12th day, the rumor would have has to all the 1000 employees

Step-by-step explanation:

Given the data in the question;

so, lets consider the rumor spreading thorough the company of 1000 employee;

the given model is; r_{n+1} = r_{n} + 1000kr_{n} ( 1000 - r_{n} )

where k is the parameter that depends on how fast the rumor spreads, n is the number of days.

now, lets assume k = 0.0001, lets also assume r₀ = 4

so to find how soon all 1000 employees  will have heard the rumor  ;

let n be;

then r1 will be;

r1 = r₀ + ( 0.001)r₀(1000-r₀ )

so

r1 = 4 + ( 0.001) × 4× (1000 - 4 )

r1 = 7.984

r2 will be;

r2 = r1 + ( 0.001)r1(1000-r1 )

r2 =  7.984 + ( 0.001) × 7.984 × (1000 - 7.984 )

r2 = 15.904255744

   

r3  will be;

r3 = r2 + ( 0.001)r2(1000-r2 )  

r3 = 15.904255744 + ( 0.001) × 15.904255744 × (1000 - 15.904255744 )

r3 = 31.555566137

Using the same formula and procedure by substituting n = 1,2,3,4,5,6,7,8,9,10,11,12.

we will have;

n        rₙ

0        4

1        7.984

2       15.904255744

3       31.555566137

4       62.1153785

5       120.372437

6       226.25535

7       401.319217

8       641.58132

9       871.53605

10     983.497013

11      999.727651

12     999.999926

Therefore, On the 12th day, the rumor would have has to all the 1000 employees

 

5 0
3 years ago
B is a number larger than 1
Ulleksa [173]
B is greater than 1, so B>1
3 0
3 years ago
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