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saw5 [17]
3 years ago
13

1/8% is what as a decimal

Mathematics
1 answer:
vlabodo [156]3 years ago
3 0

Answer:

\large\boxed{\dfrac{1}{8}\%=\dfrac{1}{800}}

Step-by-step explanation:

p\%=\dfrac{p}{100}\\\\\dfrac{1}{8}\%=\dfrac{\frac{1}{8}}{100}=\dfrac{1}{8}\cdot\dfrac{1}{100}=\dfrac{1}{800}\\\\\text{other method}\\\\\text{Convert the fraction to the decimal:}\\\\\dfrac{1}{8}=0.125\to\dfrac{1}{8}\%=0.125\%\\\\0.125\%=\dfrac{0.125}{100}=\dfrac{0.125\cdot1000}{100\cdot1000}=\dfrac{125}{100000}=\dfrac{125:125}{100000:125}=\dfrac{1}{800}

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Question 1
Alexxx [7]

Answer:

Water needed for pool = 486 cubic feet

Plastic liner required for the pool = 298.3 feet

Step-by-step explanation:

Top view of the pool is a composite figure, having one rectangle and a trapezoid.

1). Water needed for the pool = volume of the pool

Volume of the pool = Area of the base × Depth

                               = (Area of the rectangle + Area of the trapezoid)× depth  

Area of the trapezoid = \frac{1}{2}(b_{1}+b_{2})\times h

                                    = \frac{1}{2}(11+9)\times (12-1.5)

                                    = 105 ft²

Area of the rectangle = Length × width

                                    = 11 × 1.5

                                    = 16.5 ft²

Now, volume of the pool = (105 + 16.5) × 4

                                          = 121.5 × 4

                                          = 486 cubic feet

b). Liner required = surface area of the pool excluding top

                             = Surface area of the walls + Area of the pool base

                             = (Perimeter of the pool) × depth + area of the base

                             = (12 + 11 + 1.5 + 10.7 + 9)×4 + 121.5

                             = 176.8 + 121.5

                             = 298.3 square feet

Therefore, amount of water required = 486 cubic feet

liner needed = 298.3 square feet                                  

8 0
2 years ago
Solve the problem 8.62 - 1/5
aliya0001 [1]
8.42 because 1/5 = 0.2
7 0
3 years ago
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