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2 years ago

How would I find the are without height and what would the formula be

Mathematics

1 answer:

gregori [183]2 years ago

8 0

The height is 6tan(60)=10.39 then plug that in to trapezoid area formula
(11+6+15)/2*10.39=166.24

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Which describes how to graph g (x) = RootIndex 3 StartRoot x minus 5 EndRoot + 7 by transforming the parent function?

ratelena [41]

Answer:

$f(x) =\sqrt[3]{x}$

Step-by-step explanation:

Hello!

Considering the parent function, as the most simple function that preserves the definition. Let's take the function given:

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To have the the parent function, we must find the parent one, let's call it by f(x).

$f(x) =\sqrt[3]{x}$

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Check below a graphical approach of those. The upper one is g(x) and the lower f(x), its parent one.

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3 years ago

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2 years ago

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Alexeev081 [22]

Answer:46

Step-by-step explanation:Regular polygons are shapes made of straight lines with certain relationships among their lengths. For instance, a square has 4 sides, all the same length. A regular pentagon has 5 sides, all the same length. For these shapes, there are formulas for finding the area. But for irregular polygons, which are made of straight lines of any length, there are no formulas, and you need to be a little creative to find the area. Fortunately, any polygon may be divided into triangles, and there is a simple formula for the area of triangles.

Label the vertices (points) of the polygon starting with 1 at an arbitrary vertex and continuing clockwise around the polygon. There should be as many vertices as there are sides. E.g. for a pentagon (five sides) there will be five vertices.

Draw a line from vertex 1 to vertex 3. This will make one triangle, with vertices 1, 2, and 3. If there are only 4 sides, it will also make a triangle with vertices 1, 3 and 4.If the polygon has more than 4 sides, draw a line from vertex 3 to vertex 5. Continue in this way until you run out of vertices.

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Add up the areas, and this is the area of the polygon.

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3 years ago

Read 2 more answers

Use the "mixed partials" check to see if the following differential equation is exact. If it is exact find a function F(x,y) who

Arturiano [62]

We have

$(-3xy^2+y)_y=--6xy+1$

and

$(-3x^2y+x)_x=-6xy+1$

so the equation is indeed exact. So we want to find a function $F(x,y)=C$ such that

$F_x=-3xy^2+y$

$F_y=-3x^2y+x$

Integrating both sides of the first equation wrt $x$ gives

$F(x,y)=-\dfrac32x^2y^2+xy+f(y)$

Differentiating both sides wrt $y$ gives

$F_y=-3x^2y+x=-3x^2y+x+f_y\implies f_y=0\implies f(y)=C$

So we have

$F(x,y)=-\dfrac32x^2y^2+xy+C=C$

$F(x,y)=\boxed{-\dfrac32x^2y^2+xy=C}$

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3 years ago

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Mandarinka [93]

According to the theorem:
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Here it says that , it will be smallest which is false.

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3 years ago

How would I find the are without height and what would the formula be​

How would I find the are without height and what would the formula be