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Marta_Voda [28]
4 years ago
12

David used part of $100,000 to purchase a house. Of the remaining portion, he invested 1 3 of it at 4 percent simple annual inte

rest and 2 3 of it at 6 percent simple annual interest. If after a year the income from the two investments totaled $320, what was the purchase price of the house?
Business
1 answer:
VikaD [51]4 years ago
4 0

Answer:

The purchase price of the house is $94,000

Explanation:

Let the amount invested by David be b, then the amount used to purchase the house would be 100,000 - b

If he invested 1/3 of it at 4 percent simple annual interest and 2/3 of it at 6 percent simple annual interest. If after a year the income from the two investments totaled $320

Then,

\frac{1}{3}b × 4% + \frac{2}{3}b × 6% = 320

\frac{b}{3} × \frac{4}{100} + \frac{2b}{3} × \frac{6}{100}  = 320

\frac{4b}{300} + \frac{12b}{300} = 320

\frac{16b}{300} = 320

16b = 320 × 300

b = 320 × 300/16

b = 6,000

Therefore, the cost of the house (100,000 - b)

= 100,000 - 6,000

= $94,000

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Answer:

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7 0
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ZanzabumX [31]

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8 0
3 years ago
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