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Semmy [17]
3 years ago
14

I need help with this math problem ???

Mathematics
1 answer:
photoshop1234 [79]3 years ago
5 0

Answer:


Step-by-step explanation:


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Solve using zero property : (x-7)(x+10) = 0
Alla [95]

Answer:

Step-by-step explanation:

Aight

so

x^2+3x−70=0

x−7=0 or x+10=0

x=7 or x=−10

8 0
4 years ago
ANSWER ASAP!!! PLEASE... I really need an answer ;-; ..
arsen [322]

1:59 pm is 13:59, 13:59 - 06:31 = 07:28

Answer: 7 hours 28 minutes to reply

2.,3. On a "date" at 6:31 am when he already has a girlfriend?   Dump him and don't look back.



3 0
3 years ago
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Tv originally cost $400 if the price of the TV increase by 15% what is the new price ​
Verizon [17]

Answer:

$460

Step-by-step explanation:

Thus, a product that normally costs $400 with a 15 percent discount will cost you $340.00, and you saved $60.00. You can also calculate how much you save by simply moving the period in 15.00 percent two spaces to the left, and then multiply the result by $400 as follows: $400 x .15 = $60.00 savings.

3 0
3 years ago
QUICK ANSWER THIS!!!<br> j/-2+7=−12
VMariaS [17]

Answer:

38

Step-by-step explanation:

j/-2=-19

j=38

5 0
3 years ago
Read 2 more answers
Ok whoever answers this correct will get 100 brainly points
Snezhnost [94]

Answer:

We are given an area and three different widths and we need to determine the corresponding length and perimeter.  

The first width that is provided is 4 yards and to get an area of 100 we need to multiply it by 25 yards.  This would mean that our length is 25 yards and our perimeter would be 2(l + w) which is 2(25 + 4) = 58 yards.

The second width that is given is 5 yards and in order to get an area of 100 yards we need to multiply by 20 yards.  This would mean that our length is 20 yards and our perimeter would be 2(l + w) which is 2(20 + 5) = 50 yards.

The final width that is given is 10 yards and in order to get an area of 100 yards we need to multiply by 10.  This would mean that our length is 10 yards and our perimeter would be 2(l + w) which is 2(10 + 10) = 40 yards.

Therefore the field that would require the least amount of fencing (the smallest perimeter) is option C, field #3.

<u><em>Hope this helps!</em></u>

3 0
2 years ago
Read 2 more answers
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