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creativ13 [48]
3 years ago
15

Matthew made a fruit salad, in which the ratio of blueberries to red grapes is 8:6. If Matthew used 28 blueberries, how many red

grapes did he use? [Type your answer as a number.]
PLS ANSWER FAST
Mathematics
1 answer:
Inga [223]3 years ago
4 0

Answer:

Step-by-step explanation:

Let's look at some other ratios that equal 8:6  We could increase them or decrease them.  For instance if we cut one in half we cut the other one in half, so 8:6 would be the same ratio as 4:3.  With the same thinking if we double one we double the other so 8:6 s the same ratio as  16:12.  Now, we want to go from 8 to 28.  What do we multiply 8 by to get to it?  Or, it might be easier to use 4:3 and see what you multiply 4 by.  Then you multiply 3 by that same number to get the other number.

Let me know if that doesn't make sense.  

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If 2 angles are vertical and one angle is 44 degrees,find the other angle?
grandymaker [24]

Answer:

Step-by-step explanation:

Then the other angle must be 44 degrees as well.

8 0
2 years ago
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Determine whether each set is finite or infinite. the set of fractions between 1 and 2.
yuradex [85]
The set of fractions between 1 and 2 are infinite.
3 0
3 years ago
Desmond measured a city park and made a scale drawing. The scale he used was 1 centimeter: 9 meters. The actual width of the soc
kupik [55]

Answer:

6 cm

Step-by-step explanation:

1 cm : 9 meters -->  1cm/9m

? cm : 54 meters -->  ?cm/54m

\frac{1}{9}=\frac{?}{54}; 54*\frac{1}{9}=?;6=?

7 0
3 years ago
I’m confused and don’t have an angle tool to even try to do the question
yanalaym [24]
<h3>Answer:   40</h3>

=================================================

Explanation:

JQ is longer than QN. We can see this visually, but the rule for something like this is the segment from the vertex to the centroid is longer compared to the segment that spans from the centroid to the midpoint.

See the diagram below.

The ratio of these two lengths is 2:1, meaning that JQ is twice as long compared to QN. This is one property of the segments that form when we construct the centroid (recall that the centroid is the intersection of the medians)

We know that JN = 60

Let x = JQ and y = QN

The ratio of x to y is x/y and this is 2/1

x/y = 2/1

1*x = y*2

x = 2y

Now use the segment addition postulate

JQ + QN = JN

x + y = 60

2y + y = 60

3y = 60

y = 60/3

y = 20

QN = 20

JQ = 2*y = 2*QN = 2*20 = 40

--------------

We have

JQ = 40 and QN = 20

We see that JQ is twice as larger as QN and that JQ + QN is equal to 60.

7 0
3 years ago
The expression (a^2 + b^2)^2 is equivalent to
Alexxandr [17]

Answer:

Step-by-step explanation:

(x + y)² = x² + 2xy + y²

(a² + b²)²  = (a²)² + 2*a²*b² + (b²)²      {x = a² ;  y = b²}

                = a⁴ +2a²b² + b⁴    

6 0
3 years ago
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