It doesn't matter what the circumference is. Whether it's a circle that's
small enough to fit on the end of your pinky, or a circle big enough for the
Earth to fit through it, the diameter is always
(the circumference) divided by (pi) .
If the circumference is 175.84, then the diameter is 175.84/π .
For 'pi', let's use 3.14 .
Then, the diameter is
175.84 / 3.14 = <em>56 .</em>
56 can't be the exact diameter, because we used an approximation for 'pi'.
But it's close to the truth as 3.14 is.
Circunference=pi times diameter
diameter=16in
circunfernce=16pi in
that is exact because pi is irrational
if we were to aprox pi to 3.14 hen
16 times 3.14=50.24
so answer is 16pi or 50.24 in
Answer:
y= -2/5+5
Step-by-step explanation:
A line must always be written in the form y= and the line given is not. Dividing both sides of the equation by 2 you get y=5/2x-4. This is the equation of the line given.
Perpendicular line have gradients that, when they are multiplied, they are equal to -1
The line given multiplied by the gradient of the line(the one required to find)= - 1. That is 5/2×line= -1.
Dividing both sides of the equation by 5/2 you'll get - 2/5. This is the gradient of the line required.
Using the general formula y=mx+c substitute the gradient into the equation. You'll get something like this y= -2/5x+c.
Substitute the given point into the equation. You'll get something like this 3= -2/5(5)+c.
Calculate the value of c. You'll get c=5.
Substitute the value of c into the original equation. You'll get something like this y= -2/5+5
This is the equation: y= -2/5+5
The answer is 400 degrees because 325 + 75 = 400 degrees
Answer:
20%
Step-by-step explanation:
We are asked to find the proportion of of scores in a normal distribution between the mean (z = 0.00) and z = +0.52.
We will use normal distribution table to find area under normal distribution curve corresponding to given score as:
![P(0.00](https://tex.z-dn.net/?f=P%280.00%3Cz%3C0.52%29%3DP%28z%3C0.52%29-P%28z%3C0.00%29)
Using normal distribution table, we will get:
![P(0.00](https://tex.z-dn.net/?f=P%280.00%3Cz%3C0.52%29%3D0.69847%20-0.50000)
![P(0.00](https://tex.z-dn.net/?f=P%280.00%3Cz%3C0.52%29%3D0.19847)
![P(0.00](https://tex.z-dn.net/?f=P%280.00%3Cz%3C0.52%29%3D19.847%5C%25)
![P(0.00](https://tex.z-dn.net/?f=P%280.00%3Cz%3C0.52%29%5Capprox%2020%5C%25)
Therefore, approximately 20% of scores in a normal distribution between the given z-scores.