So this is taking this equation and plugging it into the quadratic formula -b+- (sqrt (b^2)-(4)ac)/2a so your A value is 1 B value is 3 and C value is -5 so it’s B&E
Here is the solution based on the given situation above.
Given: 450 kg = weight limit of the elevator
750 kg = current weight of the group of passengers
? = number of passengers who weigh 70 kgs that need to get off the elevator
So to get the answer, first we need to deduct 450kg from 750 kgs to get the excess weight. So 750 - 450 is 300kgs. Next, we divide 300 by 70kgs to get the number of passengers that need to get off so 300/70 is 4.3. Therefore, there should be 4 passengers who weigh 70 kilograms that need to get off the elevator.
Answer:
Health inspector:7,14,21,28
Fire inspector:12,24,36,48
They will both be there on day 84
Answer:
4) C
5) C
Step-by-step explanation:
The expression of sinU as a fraction is 12/13
Find the diagram attached.
To get the fraction represented by sinU, we will use the SOH CA TOA identity.
From the diagram;
- Opposite = ST = 12 (angle opposite to m<U)
Since sin theta = opp/hyp
SinU = ST/SU
SinU = 12/13
Hence the expression of sinU as a fraction is 12/13
Learn more on SOH CAH TOA here: brainly.com/question/20734777
