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4 years ago

Please help!!!!! My test is due tomorrow!!!

Mathematics

1 answer:

alex41 [277]4 years ago

5 0

Answer:

33.6 years

Step-by-step explanation:

First, you add all the months together. 870+600+540+200+150+60=2420

Then, you divide by 6. 2420/6=403.333333

Then you divide by 12 to get it in years.

403.33333333/12= 33.61

Then round down to get 33.6 years old.

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The length of a rectangular prism is 3 1/2 times as long as the width. The height is 1/4 of the width. The width is 3 cm. Determ

poizon [28]

Answer:

Volume of the rectangular prism will be $23.625cm^3$

Step-by-step explanation:

We have given that length of the prism $length=3\frac{1}{2}width=\frac{7}{2}width$

Height $=\frac{1}{4}width$

We have given width = 3 cm

So length = $\frac{7}{2}\times 3=\frac{21}{2}=10.5cm$

Height h = $\frac{1}{4}\times 3=\frac{3}{4}=0.75cm$

We know that volume of rectangular prism is given by

$V=length\times width\times height=10.5\times 3\times 0.75=23.625cm^3$

3 0

4 years ago

Complete the equation below to show a way to write 5/38 as a fraction

vaieri [72.5K]

5/38 is 0.13 because you have to divide them

6 0

4 years ago

If x ≠ -2, then 5x2 -20/5x+10 =

MissTica

Answer:

$x-2\, ,x\neq -2$

Step-by-step explanation:

So we have the expression:

$\frac{5x^2-20}{5x+10}\, ,x\neq -2$

For both the numerator and the denominator, factor out a 5:

$\frac{5(x^2-4)}{5(x+2)}\, ,x\neq-2$

The term in the numerator can be factored. This is the difference of two squares pattern:

$\frac{5(x-2)(x+2)}{5(x+2)}\, ,x\neq-2$

Both layers have a 5(x+2). Cancel them, Since we know that x cannot be -2, we can safely do so:

$x-2\, ,x\neq -2$

And we're done!

Notes:

If we weren't told that x ≠ -2, then we cannot divide them because if x did equal -2, the equation would be undefined. However, since we were given that, we can simplify.

However, even if we weren't given x ≠ -2, we can still simplify, but we need to add the restraint ourselves. This must be done, or else the equation won't be correct.

6 0

4 years ago

A circle passes through point (−2, −1) and its center is at (2, −1). Which equation represents the circle?

Vladimir [108]

Answer:

A) (x − 2)2 + (y + 1)2 = 16

please give me brainliest

Step-by-step explanation:

center: (2, −1)

(x − 2)2 + (y + 1)2

radius: 4

4^2 = 16

8 0

3 years ago

Find The derivative of:(cosx/1+sinx)^3

forsale [732]

Answer:

$-\frac{3 \cdot cos^2x}{(1+sinx)^3}$

Step-by-step explanation:

$y = (\frac{cosx}{1+sinx})^3\\\\\frac{dy}{dx} = 3 \cdot (\frac{cosx}{1+sinx})^2 \cdot \frac{dy}{dx}(\frac{cosx}{1+sinx})$ $[ y = x^n\ \ \ => \ \ \ \frac{dy}{dx} = b \cdot x^{n-1} \ ]$

$= 3 \cdot (\frac{cosx}{1+sinx})^2 \cdot \frac{(1+sin x(-sinx) - cosx(cosx)}{(1+sinx)^2}\\\\$ $[\ \frac{u}{v} = \frac{v \dcot u'- u \cdot v'}{v^2}\ ]$

$= 3 \cdot (\frac{cosx}{1+sinx})^2 \cdot \frac{-sin x-sin^2x- cos^2x}{(1+sinx)^2}\\\\= 3 \cdot (\frac{cosx}{1+sinx})^2 \cdot \frac{-sin x- (sin^2x+ cos^2x)}{(1+sinx)^2}\\\\= 3 \cdot (\frac{cosx}{1+sinx})^2 \cdot \frac{-sin x-1}{(1+sinx)^2}\\\\= 3 \cdot (\frac{cosx}{1+sinx})^2 \cdot \frac{-1 \cdot(sin x+1)}{(1+sinx)^2}\\\\= 3 \cdot (\frac{cosx}{1+sinx})^2 \cdot \frac{-1}{(1+sinx)}\\\\$

$= -3 \cdot \frac{cos^2x}{(1+sinx)^3}$

5 0

3 years ago