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Natali [406]
3 years ago
11

A circle passes through point (−2, −1) and its center is at (2, −1). Which equation represents the circle?

Mathematics
1 answer:
Vladimir [108]3 years ago
8 0

Answer:

A) (x − 2)2 + (y + 1)2 = 16

please give me brainliest

Step-by-step explanation:

center: (2, −1)

(x − 2)2 + (y + 1)2

radius: 4

4^2 = 16

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Which Mean Absolute Deviation represents more consistency? 15.2 or 10.9
Firdavs [7]

Answer:

10.9

Step-by-step Explanation:

The Mean Absolute Deviation of a given data set tells us how far apart, on average, each data value is to the mean of the data set.

The smaller the Mean Absolute Deviation of a given data set is, the closer each data value is to the mean. This also implies less variability of the data set.

Invariably, the smaller the M.A.D, which connotes less variability, the more consistent the data set is.

Therefore, a M.A.D of 10.9 represents more consistency than a M.A.D of 15.2

3 0
3 years ago
Determine whether the following sequence converges or diverges and describe whether it does do so monotonically or by oscillatio
earnstyle [38]

Answer:

D. The sequence diverges by oscillation.

Step-by-step explanation:

an = (-1.00000004)n

From root test

L = Lim n->infinity (|an|)(1/n)

==> L = Lim n->infinity (|-1.00000004n|)(1/n)

==> L = Lim n->infinity (|-1.00000004|n)(1/n)

==> L = Lim n->infinity |-1.00000004|

==> L = 1.00000004 > 1

Hence series diverges.

6 0
3 years ago
What are the zeros of the quadratic function f(x) = 6x ^ 2 - 24x + 1 ?
ZanzabumX [31]

Answer:

x = \frac{12+\sqrt{138} }{6} and x = \frac{12-\sqrt{138} }{6}

Step-by-step explanation:

Let's use the quadratic formula, which states that for a quadratic of the form ax² + bc + c, the zeroes are: x=\frac{-b+\sqrt{b^2-4ac} }{2a} or x=\frac{-b-\sqrt{b^2-4ac} }{2a}.

Here, a = 6, b = -24, and c = 1. Plug these in:

x=\frac{-b+\sqrt{b^2-4ac} }{2a}

x=\frac{-(-24)+\sqrt{(-24)^2-4*6*1} }{2*6}=\frac{24+\sqrt{552} }{12}=\frac{24+2\sqrt{138} }{12} =\frac{12+\sqrt{138} }{6}

AND

x=\frac{-b-\sqrt{b^2-4ac} }{2a}

x=\frac{-(-24)-\sqrt{(-24)^2-4*6*1} }{2*6}=\frac{24-\sqrt{552} }{12}=\frac{24-2\sqrt{138} }{12} =\frac{12-\sqrt{138} }{6}

Thus, the zeroes are: x = \frac{12+\sqrt{138} }{6} and x = \frac{12-\sqrt{138} }{6}.

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