If y = cos(kt), then its first two derivatives are
y' = -k sin(kt)
y'' = -k² cos(kt)
Substituting y and y'' into 49y'' = -16y gives
-49k² cos(kt) = -15 cos(kt)
⇒ 49k² = 15
⇒ k² = 15/49
⇒ k = ±√15/7
Note that both values of k give the same solution y = cos(√15/7 t) since cosine is even.
<u>Answer:</u>
-2
<u>Step-by-step explanation:</u>
We have been given a function f(x)=\frac{-2x}{x+1} and we are asked to find the horizontal asymptote of our given function.
Recalling the rules for a horizontal asymptote:
1. If the numerator and denominator have equal degree, the horizontal asymptote will be the ratio of the leading coefficients.
2. If the polynomial of denominator has larger degree than the numerator, then the horizontal asymptote will be the x-axis or y=0.
3. If the polynomial of numerator has larger degree than denominator, then the function has no horizontal asymptote.
Here, the numerator and denominator are of the same degree. So the horizontal asymptote will be the ratio of the coefficients.
Horizontal asymptote =
= -2
Answer:
D
Step-by-step explanation: