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Misha Larkins [42]
3 years ago
8

Chris wanted to transform the graph of the parent function Y= cot (x) by horizontally compressing it so that it has a period of

2/π units, horizontally Terslating it π/4 units to the right, and vertically translating it 1 unit up. To do so, he graphed the function y= cot (2x-π/4)+1 as shown. What did he do wrong?​
Mathematics
2 answers:
Anastasy [175]3 years ago
6 0

Answer:

The answer is C: He graphed the function y=cot(2x-pi/4)+1 correctly but it was not the right function to graph. He should have graphed y=cot(2x-pi/2)+1.

Step-by-step explanation:

The reason why it is C is because we want a period of pi/2, which would mean that b must be equal to 2 (if you use the period equation for tan and cot, pi/b, in order for pi/b to be equal to pi/2, b must be 2). The form for a trigonometric function is: y = acotb(x-h)+k. And if you notice, the equation he uses has the b already distributed inside the parenthesis, which means that both x and h were already multiplied. If we divide 2x and pi/4 by two, we get x, but h becomes pi/8, which is not equal to pi/4 as required by the problem. The correct equation would be: y = cot(2x-pi/2)+1 because when you divide out the two from inside the parenthesis, you get: y = cot2(x-pi/4)+1, which is the equation that he should've graphed.

I hope this helped you out!

If you have any further questions don't be afraid to ask.

pashok25 [27]3 years ago
3 0

Answer:

He didn't calculate the b-value correctly.

Step-by-step explanation:

The given parent function is:

y =  \cot(x)

The transformation is of the form:

y =a  \cot(bx + c)  + d

The period is given by

\frac{\pi}{b}

If we want the new function to have a period of

\frac{2}{\pi}

Then we solve the following equation for b.

\frac{\pi}{b}  =  \frac{2}{\pi}

b =  \frac{ {\pi}^{2} }{2}

-  \frac{c}{b}

will translate the graph horizontally to the right by

\frac{c}{b}

units.

+d shifts the graph up by d units.

The new function then becomes:

y =  \cot(  \frac{ {\pi}^{2} }{2}  (x  -  \frac{\pi}{4} ) )+1

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Answer:

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Step-by-step explanation:

It is given in the question functions f(x) as 3x+2 and g(x)=5-6x.

It is required to find $(f \circ g)(x)$ and $(g \circ f)(x)$.

To find $(f \circ g)(x)$, substitute g(x) for x in f(x) and simplify the expression.

To find $(g \circ f)(x)$, substitute f(x) for x in g(x) and simplify the expression.

Step 1 of 2

Substitute g(x) for x in f(x) and simplify the expression.

$$\begin{aligned}&(f \circ g)(x)=f(5-6 x) \\&(f \circ g)(x)=3(5-6 x)+2 \\&(f \circ g)(x)=15-18 x+2 \\&(f \circ g)(x)=17-18 x\end{aligned}$$

Step 2 of 2

Substitute f(x) for x in g(x) and simplify the expression.

$$\begin{aligned}&(g \circ f)(x)=g(3 x+2) \\&(g \circ f)(x)=5-6(3 x+2) \\&(g \circ f)(x)=5-18 x-12 \\&(g \circ f)(x)=-7-18 x\end{aligned}$$

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Step-by-step explanation:

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ANSWER

See sample space below

EXPLANATION

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When two fair dice are rolled, the possible by outcomes are:

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Answer:

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Step-by-step explanation:

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In the above question, they are asking you for the Loan duration

The Formula for Loan duration(T) =

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