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4 years ago

You are building a rectangular flowerbed for your back yard. The flowerbed will surround the flowers and sit on the ground. The

Mathematics

1 answer:

valentinak56 [21]4 years ago

4 0

Given parameters:

Dimension of the flowerbed = 4ft by 7ft

Unknown:

Number of feet to build the flowerbed = ?

Since the flowerbed will be surrounding the flows, we should simply find the perimeter of the bed.

This is a rectangular area;

Perimeter = 2(L + B)

Input the parameters and solve;

Perimeter = 2 (4 + 7)

Perimeter = 2 x 11 = 22cm

The perimeter of the board is 22cm

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What is the solution of the equation<br> √3x+2=√2x-2

MakcuM [25]

Step-by-step explanation:

$\sqrt{3 x - \sqrt{2x = 4} }$

7 0

3 years ago

I’m lost again can somebody help asap ??

serious [3.7K]

Fully detailed and equipped information process right below. The answer for this question is "25" (simplified form).

$\mathbf{2^{28} \times \Bigg(\dfrac{5^{- 2}}{2^3} \Bigg)^4 \times \Bigg(5^{- 5} \times 2^8 \times 1 \Bigg)^{- 2}}$

$\mathbf{2^{28} \times \Bigg(\dfrac{5^{- 2}}{2^3} \Bigg)^4 \times \Bigg(2^8 \times 1 \times \dfrac{1}{5^5} \Bigg)^{- 2}}$

$\mathbf{2^{28} \times \Bigg(\dfrac{5^{- 2}}{2^3} \Bigg)^4 \times \Bigg(1 \times \dfrac{2^8 \times 1}{5^5} \Bigg)^{- 2}}$

$\mathbf{2^{28} \times \Bigg(\dfrac{5^{- 2}}{2^3} \Bigg)^4 \times \Bigg(1 \times \dfrac{256}{3125} \Bigg)^{- 2}}$

$\mathbf{2^{28} \times \Bigg(\dfrac{5^{- 2}}{2^3} \Bigg)^4 \times \Bigg(\dfrac{3125}{256} \Bigg)^2}$

$\mathbf{2^{28} \times \Bigg(\dfrac{5^{- 2}}{2^3} \Bigg)^4 \times \dfrac{3125^2}{256^2}}$

$\mathbf{2^{28} \times \Bigg(\dfrac{1}{2^3 \times 5^2} \Bigg)^4 \times \dfrac{3125^2}{256^2}}$

$\mathbf{2^{28} \times \Bigg(\dfrac{1^4}{(2^3 \times 5^2)^4} \Bigg) \times \dfrac{3125^2}{256^2}}$

$\mathbf{2^{28} \times \Bigg(\dfrac{1^4}{(5^2)^4 \times (2^3)^4} \Bigg) \times \dfrac{3125^2}{256^2}}$

$\mathbf{2^{28} \times \dfrac{1}{2^{12} \times 5^8} \times \dfrac{3125^2}{256^2}}$

$\mathbf{\dfrac{3125^2 \times 1 \times 2^{28}}{256^2 \times 5^8 \times 2^{12}}}$

$\mathbf{\dfrac{2^{(28 - 12)} \times 3125^2}{256^2 \times 5^8}}$

$\mathbf{\dfrac{2^{16} \times 3125^2}{256^2 \times 5^8}}$

$\mathbf{\dfrac{2^{16} \times (5^5)^2}{(2^8)^2 \times 5^8}}$

$\mathbf{\dfrac{2^{16} \times 5^{10}}{2^{16} \times 5^8}}$

$\mathbf{\dfrac{2^{16} \times 5^{10 - 8}}{2^{16}}}$

$\mathbf{\dfrac{5^{10 - 8}}{1}}$

$\mathbf{\therefore \quad 5^2}$

$\mathbf{\therefore \quad 25}$

$\boxed{\mathbf{\underline{\therefore \quad Final \: \: Answer \: \: is: \: 25}}}$

Hope it helps.

7 0

4 years ago

A cube has six sides that are numbered 1 to 6. The sides numbered 1, 3, and 5 are yellow, and the sides numbered 2, 4, and 6 are

mr_godi [17]

0, all yellow sides are odd so you get one or the other, not both

6 0

3 years ago

Mrs. Adesso wants to take her class on a trip to either the science center or the natural history museum. The science center cha

blsea [12.9K]

Answer:

Step-by-step explanation:

see picture for work!

8 0

3 years ago

Write in slope-intercept form an equation of the line that passes through the given points.

Kipish [7]

Answer:

y = 2x

Step-by-step explanation:

Let's first find the slope:

m = (y₂ - y₁)/(x₂ - x₁)

m = (6 - 4)/(3 - 2) = 2/1 = 2

Now let's use point-slope form:

y - y₁ = m(x - x₁)

(For x₁ and y₁, you can use either (2,4) or (3,6), but I'm gonna use (2,4))

y - 4 = 2(x - 2)

y - 4 = 2x - 4

y = 2x

That's your answer.

Hope this helps, and hope you learned something!

3 0

3 years ago