Ask question

Ask question

All categories

2 years ago

6

What is the answer to page 156-157 on chapter 4 proportions relationship.

1 answer:

timurjin [86]2 years ago

4 0

Proportional relationships<span>: A </span>relationship<span> between two equal ratios. Proportions are the comparison of two equal ratios. Therefore, </span>proportionalrelationships<span> are </span>relationships<span> between two equal ratios. For example, oranges are sold in a bag of 5 for $2. The ratio of oranges to their cost is 5:2 or.</span><span>In mathematics, two variables are proportional if a change in one is always accompanied by a change in the other, and if the changes are always related by use of a constant multiplier. The constant is called the coefficient of proportionality or proportionality constant.</span>

You might be interested in

Will award brainiest!!

vagabundo [1.1K]

Answer:

The best estimate of the probability of getting a green marble from this bag of 50 marbles is 1/3.

Step-by-step explanation:

Andre gets 1 green marble out of 4 trials.

For Andre, the probability of getting 1 green marble is 1/4.

Jada gets 5 green marbles out of 12 trials.

For Jada, the probability of getting 1 green marble is 5/12.

Noah gets 3 green marbles out of 9 trials.

For Noah, the probability of getting 1 green marble is 3/9.

Hence, the best estimate of the probability of getting a green marble from this bag = (1/4 + 5/12 + 3/9)/3 = [(9 + 15 + 12)/36]/3 = 1/3.

3 0

1 year ago

11 more than four times a number is 39

Aliun [14]

Hello!

Your answer is: 7

(X = "<em>A number</em>")

<em>"11 more than four times a number is 39"</em> in equation form is: 4X + 11 = 39

to solve, first subtract 11 from both sides:

4X = 28

then divide both sides by 4 to get:

X = 7

I hope this helps, and have a nice day!

4 0

3 years ago

If log2 5 = k, determine an expression for log32 5 in terms of k.

lukranit [14]

Answer:

$log_3_2(5)=\frac{1}{5} k$

Step-by-step explanation:

Let's start by using change of base property:

$log_b(x)=\frac{log_a(x)}{log_a(b)}$

So, for $log_2(5)$

$log_2(5)=k=\frac{log(5)}{log(2)}\hspace{10}(1)$

Now, using change of base for $log_3_2(5)$

$log_3_2(5)=\frac{log(5)}{log(32)}$

You can express $32$ as:

$2^5$

Using reduction of power property:

$log_z(x^y)=ylog_z(x)$

$log(32)=log(2^5)=5log(2)$

Therefore:

$log_3_2(5)=\frac{log(5)}{5*log(2)}=\frac{1}{5} \frac{log(5)}{log(2)}\hspace{10}(2)$

As you can see the only difference between (1) and (2) is the coefficient $\frac{1}{5}$ :

So:

$\frac{log(5)}{log(2)} =k\\$

$log_3_2(5)=\frac{1}{5} \frac{log(5)}{log(2)} =\frac{1}{5} k$

6 0

2 years ago

Classify ∠2 and ∠6. Compare angle measures, and give the postulate or theorem that justifies it.

LenaWriter [7]

Answer:

Explanation

Step-by-step explanation:

Angles 2 and 6 are corresponding angles in a transversal meaning they have the same measure.

4 0

2 years ago

What is the area of a semicircle with the diameter of 15

Alina [70]

Answer:

you divide 15 by 2 to get the radius, then do pie times radius to the second power, so

3.14*7.5*7.5= 23.55

that is ur answer!

Step-by-step explanation:

7 0

2 years ago