Answer:
Solve for a
a12−3(a−1)=11+a
Write the problem as a mathematical expression.
a12−3(a−1)=11+a
Simplify each term.
a12−3a+3=11+a
Graph each side of the equation. The solution is the x-value of the point of intersection.
a≈−1.1114621,1.23792371
Step-by-step explanation:
Answer:
2
Step-by-step explanation:
1st step: solve the exponential number
2x^2=4x
3x^2=9x
2nd step: rewrite the number sentence with the exponent solved
4x-8x+8 9x+27x-30
3rd step : solve
4x-8x=-4x 9x+27x=36x
-4x+8= 36x-30=
4 6
Step 4: See what least common multiples they have in common
4 LCM =2 * 2= 4 6 LCM= 2*3=6
So the LCM is 2
Answer:
Step-by-step explanation:
The function s(x)=0.9(.82)^x models the number of subscription in tens of thousands where x represents the number of years since the trend has been observed.
s(x) represents the number of subscriptions to the Dorchester Daily in a given year.
0.9 in ten thousands represents the initial number of subscriptions to the Dorchester Daily in a given year.
0.82 represents the rate at which the number of number of subscriptions to the Dorchester Daily is declining. The rate in percentage is 100 - 82 = 12% each year.
x represents the number of years since the trend has been observed.
Answer:
So, if all the light passes through a solution without any absorption, then absorbance is zero, and percent transmittance is 100%. If all the light is absorbed, then percent transmittance is zero, and absorption is infinite.
Absorbance is the inverse of transmittance so,
A = 1/T
Beer's law (sometimes called the Beer-Lambert law) states that the absorbance is proportional to the path length, b, through the sample and the concentration of the absorbing species, c:
A ∝ b · c
As Transmittance, 
% Transmittance, 
Absorbance,
Hence, 
is the algebraic relation between absorbance and transmittance.
