How do you multiply (2r^2 5r-1)(5r^2 2r-8)?
1 answer:
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Answer: 1)
2)
Step-by-step explanation:
1) Let the function that shows the thickness of the paper after n folds,
---------(1)
Since, According to the question,
Initially the thickness of the paper = 0.6
That is, at n = 0, t(0) = 0.6
By equation (1),
Hence the function that shows the given situation,
-----------(2)
Again when we fold the paper the thickness of the paper will be doubled.
Thus, at n = 1, t(1) = 1.2
By equation (2),
Thus, the complete function is,
2) Let the function that is passing through the points (-2, 2/5) and (-1,2),
---------(1)
For f(x) = 2, x = -1
By equation (1),
---------(2)
Also, For f(x) = 2/5, x = -2
Again, By equation (1),
By substituting this value in equation (2),
We get, a = 10
Hence, from equation (1), the function that is passing through the points (-2, 2/5) and (-1,2),