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3 years ago

14

Now solve the equation 4(x+3)=8. Remember to: Build the equation on your Equation Mat with algebra tiles. Simplify the equation

using your legal moves. Record your work on your paper. Solve for x . That is, find the value of x that makes the equation true.

1 answer:

Ymorist [56]3 years ago

3 0

Answer:

x=-1

Step-by-step explanation:

4(x+3)=8

4x+12=8

4x=-4

x=-1

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Jonah has collected 91 coins worth $7.20 in his piggy bank. his collection includes only dimes and nickels. how many dimes are t

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3 years ago

Please select the best answer from the choices provided

Ira Lisetskai [31]

<u>Answer:</u>

The correct answer option is c. $\frac{1}{9a^2}$ .

<u>Step-by-step explanation:</u>

We are given an expression $(27a^{-3})^{-\frac{2}{3} }$ and we are supposed to simplify it.

We can also write $(27a^{-3})^{-\frac{2}{3} }$ as $(\frac{3^3}{a^3} )^{-\frac{2}{3} }$ .

We know the power rule (a^m)^n=a^{mn} which means that to raise a power to a power you need to multiply the exponents.

So multiplying the exponents to get:

$\frac{3^{(3.-\frac{2}{3})} }{a^{(3.\frac{2}{3})} }\\\\\frac{3^{-2}}{a^2}\\ \\\frac{1}{3^2a^2} \\\\\frac{1}{9a^2}$

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4 0

3 years ago

Determine whether the three segment lengths will produce a triangle. Type yes or no in the space provided.

tresset_1 [31]

Answer:

20 , 20 , 30 will produce a triangle

Step-by-step explanation:

* Lets study how to know if the lengths of the three segments

can formed a triangle

- It is a fact that in any triangle the sum of the smallest two sides

must be greater than the largest side

- Lets study some examples

# If the lengths of the three segments are 5 , 6 , 7

∵ 5 and 6 are the smallest

∴ 5 + 6 = 11

∵ 11 > 7 ⇒ the sum greater than the 3rd side

∴ 5 , 6 , 7 can formed a triangle

# If the lengths of the three segments are 5 , 7 , 12

∵ 5 and 7 are the smallest

∴ 5 + 7 = 12

∵ 12 = 12 ⇒ the sum equal the 3rd side

∴ 5 , 7 , 12 can not formed a triangle

# If the lengths of the three segments are 10 , 12 , 24

∵ 10 and 12 are the smallest

∴ 10 + 12 = 22

∵ 22 < 24 ⇒ the sum less than the 3rd side

∴ 10 , 12 , 24 can not formed a triangle

* Now lets solve the problem

∵ The length of the three segments are 20 , 20 , 30

∵ 20 and 20 are the smallest

∴ 20 + 20 = 40

∵ 40 > 30 ⇒ the sum greater than the 3rd side

∴ 20 , 20 , 30 will produce a triangle

5 0

2 years ago