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Svetradugi [14.3K]
3 years ago
10

Carrie and Ryan have both computed the slope of the least-squares line using data for which the standard deviation of the x-valu

es and the standard deviation of the y-values are equal. Carrie gets a value of 0.5 for the slope, and Ryan gets a value of 2. One of them is right. Which one?
Mathematics
1 answer:
alexdok [17]3 years ago
6 0

Answer:

Carrie's slope value is correct.

Step-by-step explanation:

The least square regression line is: (y -\bar y)=b_{yx} (x-\bar x)

Here b_{yx} is the slope of the line.

The formula to compute the slope is:

b_{yx}=r\frac{\sigma_{x}}{\sigma_{y}}

Here \sigma_{x} = standard deviation of <em>x</em> and \sigma_{y} = standard deviation of <em>y</em>.

It is provided that the standard deviation of <em>x</em> and <em>y</em> are equal.

So the slope of the regression line is:

b_{yx}=r\frac{\sigma_{x}}{\sigma_{y}}=r\frac{\sigma_{x}}{\sigma_{x}}=r

Thus, if the standard deviation of <em>x</em> and <em>y</em> are equal the slope of the line is same as the correlation coefficient.

The correlation coefficient is a measure used to determine the strength of the linear relationship between the variables.

It ranges from -1 to 1.

Carrie's slope value was 0.50 and Ryan's slope value was 2.

Since -1 ≤ r ≤ 1 the value of slope cannot be 2.

Thus, Ryan's slope value is incorrect.

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Claire had 4 1/6 feet of string. She used some string to hang out decorations. Now she has 1 5/6 feet of string left. How much s
vodka [1.7K]

Answer:

Length of string used by Claire = 7 / 3 feet

Step-by-step explanation:

Given:

Length of string Claire in starts = 4\frac{1}{6} feet

Length of string Claire in end = 1\frac{5}{6} feet

Find:

Length of string used by Claire

Computation:

Length of string Claire in starts = 4\frac{1}{6} feet = 25 / 6 feet

Length of string Claire in end = 1\frac{5}{6} feet = 11 / 6 feet

Length of string used by Claire = Length of string Claire in starts - Length of string Claire in end

Length of string used by Claire = [25 / 6] - [11 / 6]

BY taking LCM

Length of string used by Claire = [25 - 11] / 6

Length of string used by Claire = 14 / 6

Length of string used by Claire = 7 / 3 feet

8 0
2 years ago
Explain how you could use a number line to show that -4 + 3 and 3 + (-4) have the same value
iogann1982 [59]
Find (-4) on the number line and move 3 to the right.  You will end up at (-1).

Find (3) on the number line and move 4 to the left.  You will end up at the same value of (-1).
6 0
3 years ago
Noelle's bill was $5.56 for her breakfast sandwich, plus tax. If tax is 12%, how much, in total, did she pay
Ugo [173]

Answer:

$6.23

Step-by-step explanation:

5.56*1.12=6.2272

7 0
3 years ago
Ten college students were randomly selected. Their grade point averages​ (GPAs) when they entered the program were between 3.5 a
solong [7]

Answer:

The 95% confidence interval for the true slope is (0.03985, 0.14206).

Step-by-step explanation:

For the regression equation:

\hat y=\alpha +\hat \beta x

The (1 - <em>α</em>)% confidence interval for the regression coefficient or slope (\hat \beta ) is:

Ci=\hat \beta \pm t_{\alpha/2, (n-2)}\times SE(\hat \beta )

The regression equation for current GPA (Y) of students based on their GPA's when entering the program (X) is:

\hat Y=3.584756+0.090953 X

The summary of the regression analysis is:

Predictor          Coefficient             SE             t-stat            p-value

Constant             3.584756          0.078183       45.85075      5.66 x 10⁻¹¹

Entering GPA   0.090953          0.022162        4.103932       0.003419

The regression coefficient and standard error are:

\hat \beta = 0.090953\\SE (\hat \beta)=0.022162

The critical value of <em>t</em>  for 95% confidence level and 8 degrees of freedom is:

t_{\alpha/2, n-2}=t_{0.05/2, 10-2}=t_{0.025, 8}=2.306

Compute the 95% confidence interval for (\hat \beta ) as follows:

CI=\hat \beta \pm t_{\alpha/2, (n-2)}\times SE(\hat \beta )\\=0.090953\pm 2.306\times 0.022162\\=0.090953\pm 0.051105572\\=(0.039847428, 0.142058572)\\\approx (0.03985, 0.14206)

Thus, the 95% confidence interval for the true slope is (0.03985, 0.14206).

6 0
3 years ago
What value of x is in the solution set of 2x. 3 &gt; 11 - 5x? <br><br>a. -3<br>b. 0<br>c. 2<br>d. 4​
joja [24]

Answer:

i think option d

3 0
2 years ago
Read 2 more answers
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