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REY [17]
2 years ago
8

Find the probability of each event.

Mathematics
1 answer:
jeka57 [31]2 years ago
5 0

Using the binomial distribution, it is found that there is a 0.0108 = 1.08% probability of the coin landing tails up at least nine times.

<h3>What is the binomial distribution formula?</h3>

The formula is:

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

C_{n,x} = \frac{n!}{x!(n-x)!}

The parameters are:

  • x is the number of successes.
  • n is the number of trials.
  • p is the probability of a success on a single trial.

In this problem:

  • The coin is fair, hence p = 0.5.
  • The coin is tossed 10 times, hence n = 10.

The probability that is lands tails up at least nine times is given by:

P(X \geq 9) = P(X = 9) + P(X = 10)

In which:

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 9) = C_{10,9}.(0.5)^{9}.(0.5)^{1} = 0.0098

P(X = 10) = C_{10,10}.(0.5)^{10}.(0.5)^{0} = 0.001

Hence:

P(X \geq 9) = P(X = 9) + P(X = 10) = 0.0098 + 0.001 = 0.0108

0.0108 = 1.08% probability of the coin landing tails up at least nine times.

More can be learned about the binomial distribution at brainly.com/question/24863377

#SPJ1

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