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2 years ago

What is the solution to 3|–3x + 9| = –18?

Mathematics

2 answers:

Elena-2011 [213]2 years ago

8 0

Answer:

equation has no solutions

Step-by-step explanation:

3|–3x + 9| = –18 (divide both sides by 3)

|–3x + 9| = –6

because by definition, for any value a, |a| must be non-negative

hence |–3x + 9| must give a value that is greater or equal zero

because the right side of the equation is a negative integer, hence the equation has no solutions.

Sergio039 [100]2 years ago

6 0

Answer:

X=5

Step-by-step explanation:

i hope this helps

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10. I purchased a hair-dryer for 5,400 including 8% VAT. Find the price before VAT was added. <br>

Semmy [17]

Answer:

4968

Step-by-step explanation:

432 is 8% of 5400 and after deducting 432 we get 4968.

8 0

2 years ago

4n2 - 3 = 61<br>how do I solve by square roots

NeX [460]

Answer:

n = 4 or n = -4

Step-by-step explanation:

We have: 4n² - 3 = 61.

Add 3 to both sides:

4n² = 61 + 3 = 64

Divide both sides by 4:

n² = 64/4 = 16

Square root both sides:

n = +/- √16

n = 4 or n = -4

The answers are 4 and -4.

3 0

3 years ago

Read 2 more answers

A liquid solution is slowly leaking from a container. The graph shows the milliliters of solution, y, remaining in the container

Burka [1]

Answer:

90 minutes

Step-by-step explanation:

See attachment for graph.

First, we need to determine the slope.

When y = 900, x = 0

When y = 600, x = 30

The slope is then calculated as:

m = (y2 - y1)/(x2 - x1)

m = (600 - 900)/(30 - 0)

m = -300/30

m = -10

Next, we determine the equation of the line using

y - y1 = m(x - x1)

So, we have:

y - 900 = -10(x - 0)

y - 900 = -10x

y = 900 - 10x

When the container is empty, y = 0.

So, we have:

0 = 900 - 10x

Collect Like Terms

10x = 900

Solve for x

x = 900/10

x = 90

3 0

3 years ago

34.1 ÷ 5.5 i need an explanation on this math problem how to break it down

Veseljchak [2.6K]

Nevermind I did this wrong, forget that I had a answer.

6 0

3 years ago

Give one example of when you would make a frequency table to solve the problem

RideAnS [48]

Answer:

Consider a class in which there are 40 students .There is a Mathematics test of 50 marks .Two students were absent.The Duration of test was for one and half an hour.

So Marks of students according to their roll number are 12,8,4,20,25,36,2,29,35,39,5,48,43,37,38,29,17,15,15,25,31,32,26,28,27,24,2,15,34,,50,46,48,37,28,26,45,49,24.

So in this case it would be better to prepare frequency polygon by selecting a class interval.

Class interval = 0-5,5-10,10-15,15-20,20-25,25-30,30-35,35-40,40-45,45-50.

Or 0-10,10-20,20-30,30-40,40-50.

or you can make class interval by yourself.

4 0

2 years ago