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fredd [130]
3 years ago
13

which of rhe following equations of the line is the most convient to use when there are two points identified on the line? A.)y=

mx+b. C.) x/a+y/b=1 B.) y-y1=m(x-x1) D.)y-y1=y2-y1/x2-x1(X-X1)​
Mathematics
1 answer:
adelina 88 [10]3 years ago
5 0

Answer:

A

Step-by-step explanation: I am not for sure but I would think that cuz if your dealing with lines and point you gonna end up doing slope and slope is Y=MX+B

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Which is less -.72 or -7/12
Likurg_2 [28]

ok so 7 divided by 12 is 0.5833333 repeating so -0.72 is less because the bigger one is always less in the negatives

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Unknown angle problems (with algebra)
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Answer: x = 20 degree
3x = 3×20 which is 60 degree
And the other one is 100 degree
Add all the number 100+60+20 degree is 180 degree
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3 years ago
John is creating a Thanksgiving display at the store where he works, using only canned pumpkin and canned green beans. He needs
KengaRu [80]

Answer:

90 pumpkin and 36 green beans

Step-by-step explanation:

Because there is a total of 7 parts (5+2) and I divided 126 by 7 and then put five of the 18ns (the quotient of 126 and 7) for pumpkins (so... multiply 18 by 5) then the other to times 18 is 36. And if you add them together, they equal 126.

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Basketball star Mumford ( a seven foot senior forward ) places a mirror on the ground x ft from the vase of a basketball goal .
Nataliya [291]
<span>9 feet, 2 inches
   First thing to do is determine how high above the ground Mumford's eyes are. The proportions for an adult human is that their height is about 7.5 heads tall (this includes the head), so Mumford's head is about (7*12)/7.5 = 11.2 inches tall. The eyes are about centered vertically on the head, so Mumford's eyes are about 5.6 inches from the top of his head. So his eyes are about 7*12 - 5.6 = 84 - 5.6 = 78.4 inches from the ground. Once Mumford backs up and is able to see the goal in the mirror, he's created 2 similar right triangles. One of the triangles is the distance from the mirror to Mumford and the height of Mumford's eyes from the ground. The other triangle is the distance from the mirror to directly underneath the goal and the height of the goal. They're similar triangles since the angle of incidence of a light ray matches the angle of reflection. So let's do the math. First, the 6 feet and 10 feet measurements are multiplied by 12 to convert to inches. So we have 72 inches and 120 inches. Let's set up the equation and solve: 72/78.4 = X/120
 120*72/78.4 = X
 110.2040816 = X

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8 0
4 years ago
Find sin4a and cos4α, if tanα=3
Mashcka [7]

Answer:

<h2>See the explanation.</h2>

Step-by-step explanation:

Sin2α = 2SinαCosα.

Cos2α = (Cosα)^2 - (Sinα)^2.

Sin4α can be written as Sin2(2α).

Similarly Cos4α can be written as Cos2(2α).

Sin 4\alpha = 2Sin 2\alpha \times Cos 2\alpha = 2Sin 2\alpha \times(Cos^{2} \alpha - Sin^{2} \alpha ) = 4Sin \alpha \times Cos \alpha \times (Cos^{2} \alpha - Sin^{2} \alpha )

It is given that  tanα=3.

Sinα(Sinα) =  \frac{9}{10} [Sec^{2} \alpha = 1 + 3^{2} = 10.\\Cos^{2} \alpha = \frac{1}{10} \\Sin^{2} \alpha = 1 - \frac{1}{10} = \frac{9}{10}], the values either be both positive or both negative, as the value of tanα is positive only on first and third quadrant.

Sin4α = 4\times \sqrt{(\frac{9}{10} )} \times  \sqrt{(\frac{1}{10} )} \times (\frac{1 - 9}{10} ) = -\frac{4\times8\times3}{100} = -\frac{96}{100}.

Cos4α = Cos^{2} 2\alpha  - Sin^{2} 2\alpha = (Cos^{2} \alpha - Sin^{2} \alpha )^{2} - Sin^2 {2\alpha } = (Cos^{2} \alpha - Sin^{2} \alpha )^{2} - (2Sin \alpha Cos \alpha )^{2} = (-\frac{8}{10} )^{2} - \frac{4\times9}{100} = \frac{64 - 36}{100} = \frac{28}{100} = \frac{7}{25}

7 0
3 years ago
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